All categories

3 years ago

Two coins are tossed simultaneously. Find the probability of getting

1 answer:

4 0

(i) Probability of getting two heads = 0.5*0.5 = 0.25
(Here we multiply the probability of getting a head by the probability of getting a head)

(ii) Probability of getting at least one head = 0.5*0.5 + 0.5*0.5 + 0.5*0.5 = 0.75
(Here we add the probability of getting a head and a head to the probability of getting a head and then a tail and then add the probability of getting a tail and then a head)
The second way to do this is to subtract the probability of not getting any heads (ie. getting a tail and a tail) from 1:
1 - 0.5*0.5
= 1 - 0.25
= 0.75

You might be interested in

I will give you guys 100 points if you help me for just these 5 questions please

nignag [31]

Remember that squaring something is just multiplying that number by itself.

$55^2 = 55 \times 55 = 3025$

$95^2 = 95 \times 95 = 9025$

$75^2 = 75 \times 75 = 5625$

$45^2 = 45 \times 45 = 2025$

$35^2 = 35 \times 35 = 1225$

3 0

2 years ago

Read 2 more answers

How do you solve this math problem-2(x+3y)=18

ss7ja [257]

Greetings!

Solve for x.
$-2(x+3y)=18$
Distribute the Parenthesis. How? Multiply all of the terms inside the parenthesis by the number outside the parenthesis.
$(-2)*x+(-2)*3y=18$
$-2x-6y=18$
Add 6y to both sides.
$(-2x-6y)+6y=(18)+6y$
$-2x=18+6y$
Divide both sides by -2.
$(-2x)/-2=(18+6y)/-2$
The Answer Is:
$x=-9-3y$
$x=-3y-9$

Hope this helps.
-Benjamin

7 0

2 years ago

Please I need the correct answer please

Rzqust [24]

(−1

2 )(n^3)+

1

2 n^2+4.6n+(−

1

2)(n^3)+

1

2 n^2+4.5n

−1

2 n^3+

2 n^2+4.6n+

−1

2 n^3+

2 n^2+4.5n

Combine Like Terms:

−1

2 n^3+

1

2 n^2+4.6n+

−1

2 n^3+

1

2 n^2+4.5n

=(−1

2 n^3+

−1

2 n^3)+(

1

2 n^2+

1

2 n^2)+(4.6n+4.5n)

=−n^3+n^2+9.1n

Answer:

=−n^3+n^2+9.1n

Everything underlined means its a fraction/divided hope this helps :D

8 0

2 years ago

The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me

Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0

2 years ago

8+a=21 plssssssssssssszzzz

attashe74 [19]

Answer:

Step-by-step explanation:

because a is the missing number. Well, 21 minus or - 8 is equal to 13.

8 0

2 years ago