GIVING BRAINLIEST TO THE FIRST AND CORRECT ANSWER!!!!!!!

Find the surface area of the prism.<br><br> Explain how you got your answer pls

zavuch27 [327]

Answer:

Step-by-step explanation: I’m too lazy to do it but just substitute the values into the formula of a Rectangular prism Surface Area

3 0

2 years ago

Read 2 more answers

Find the linear approximating polynomial for the following function centered at the given point a.point a. b. Find the quadratic

ZanzabumX [31]

Answer:

$(a)L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\(b)Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\(c)L(-0.23\pi)=-0.6626\\Q(-0.23\pi)=-0.6613$

Step-by-step explanation:

Given the function:

$f(x)=sin x, a=-\frac{\pi}{4}$

(a)Linear approximating polynomial

$L(x)=f(a)+f'(a)(x-a)\\f(a)=sin(-\frac{\pi}{4})=-\frac{\sqrt{2} }{2}\\f'(x)=cos x, a=-\frac{\pi}{4}\\f'(a)=cos (-\frac{\pi}{4})=\frac{\sqrt{2} }{2} \\Therefore:\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x-(-\frac{\pi}{4}))\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})$

(b)Quadratic approximating polynomial

$Q(x)=L(x)+\frac{1}{2}f''(a)(x-a)^2\\f''(x)=-sin(x), \\f''(a)=-sin(-\frac{\pi}{4})=\frac{\sqrt{2} }{2}\\Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2$

(c)When $x=-0.23\pi$

Using Linear Approximation polynomial

$L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\L(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})\\L(-0.23\pi)=-0.6626$

Using the Quadratic approximating polynomial

$Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\Q(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(-0.23\pi+\frac{\pi}{4})^2=-0.6613$

4 0

2 years ago

I tried even my parents tried nether got it correct and I don't under stand could I pleas get some help.

katrin2010 [14]

Answer:

Step-by-step explanation:

The volume of a cylinder is the base area times the height.

V=hr^2(pi), and the height is always 8 so

V=(8pi)r^2

V=(8pi)1^2=25.13

V=(8pi)2^2=4(8pi)=100.53

V=(8pi)3^2=9(8pi)=226.19

7 0

2 years ago

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When the expression 2x^2+5x-3 is written in the equivalent form (2x-1)(x+3), list the factors

madreJ [45]

hence the factors for this question are 1/2 ,- 3

hope it helps you!!!!!!!!

8 0

2 years ago

Rosa has a rectangle shaped backyard where the length is two less than twice the width. If the area of the garden is 420 square

Rudiy27

The expression for the area of a rectangle is given by:
A = (w) * (l)
Where,
l: long
w: width
the length is two less than twice the width:
l = 2w-2
Substituting the values:
420 = (w) * (2w-2)
We rewrite the expression:
210 = (w) * (w-1)
210 = w ^ 2-w
w ^ 2-w-210 = 0
The roots of the polynomial are:
w1 = -14
w2 = 15
We discard the negative root.
Width:
w = 15
Long:
l = 2w-2
l = 2 (15) -2
l = 30-2
l = 28
Answer:
the dimensions of Rosa's garden are:
w = 15 feet
l = 28 feet

5 0

3 years ago