Answer:
Step-by-step explanation:
If Thaddeus drives the whole 16 hours, the distance between them is ...
distance = speed · time
distance = 20 mi/h · 16 h
distance = 320 miles.
It is 45 miles more than that. For each hour that Ian drives, their separation distance increases by (25 mph -20 mph)·(1 h) = 5 mi. Then Ian must have driven ...
(45 mi)/(5 mi/h) = 9 h
The rest of the 16 hours is the time that Thaddeus drove: 7 hours.
___
Let x represent the time Ian drives. Then 16-x is the time Thaddeus drives. Their total distance driven is ...
distance = speed · time
365 mi = (25 mi/h)(x) + (20 mi/h)(16 h -x)
45 mi = (5 mi/h)(x) . . . . . . . . subtract 320 miles, collect terms
(45 mi)/(5 mi/h) = x = 9 h . . . . . . divide by the coefficient of x
_____
<em>Comment on the solution</em>
You may notice a similarity between the solution of this equation and the verbal discussion above. (That is intentional.) It works well to let a variable represent the amount of the highest contributor. Here, that is Ian's time, since he is driving at the fastest speed.
Answer:
6(2x - 1)
Step-by-step explanation:
Given
12x - 6 ← factor out common factor of 6 from both terms
= 6(2x - 1) ← in factored form
Answer:
46/50 is an equivalent to 23/25
1 box = 2 recorders
3 boxes = 6 recorders
5+6 = 11 recorders
Answer:
16 ribbons
Step-by-step explanation:
Given the length of the chain as 10
and there is a ribbon tied to it every , we can take the total length of the chain and divide by the measure of :
When dividing with fractions, we use the rule of 'keep/change/flip' to keep the first fractions, change the operation to multiplication and flip the second fraction.
