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Dennis_Churaev [7]
4 years ago
15

if i have 2 equal rows of marbles with none left, 3 equal rows of marbles with none left and 4 equal rows of marbles with none l

eft how many marbles do i have altogether?
Mathematics
1 answer:
maria [59]4 years ago
4 0
I think it's 29 marbles
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Can someone help (Its a photo) ill give brain list
Savatey [412]

Answer:

this is the order

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8 0
3 years ago
What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.
Ahat [919]

The value of x in the equation (x-5)^{2} +3(x-5)+9=0is x=(7+3\sqrt{3}i)/2,

(7-3\sqrt{3}i)/2.

Given equation (x-5)^{2} +3(x-5)+9=0 .

We have to find the solution of the equation.

Equation  is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes u^{2} +3u+9=0

solution of a quadratic formula

x=-b±\sqrt{b^{2} -4ac}/2a

on comparing with general form a=1,b=3, c=9

u=-3±\sqrt{3^{2} -4*1*9} /2

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=-3±3\sqrt{-27}/2

=-3±3\sqrt{3} i/2

u_{1} =-3+3\sqrt{3}/2 , u_{2}=-3-3\sqrt{3}/2

put the values of u_{1} in equation 1

x-5=u_{1}

x-5=-3+3\sqrt{3} /2

x=-3+3\sqrt{3}i/2+5

x=7+3\sqrt{3} i/2

put the values of u_{2} in  equation2

x-5=u_{2}

x-5=-3-3\sqrt{3} /2

x=7-3\sqrt{3}/2

Hence the values of x are 7+3\sqrt{3}i/2, 7-3\sqrt{3}i/2.

Learn more about equation at brainly.com/question/2972832

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5 0
2 years ago
Help me this is really hard
Andru [333]
I’m sorry but I can’t read the hole question
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3 years ago
The Greatest Show on Earth Circus Tour of 1890 hold the record for the most performers involved in a circus act. One hundred sev
Natasha_Volkova [10]

Answer:

yes

Step-by-step explanation:

175 + 263 = 438

to get 40% do 40/100=0.4

so 438 x 0.4 = 175.2

175 is about 40% of 438

3 0
3 years ago
A middle school team scored three field goals worth three points each and two touchdowns worth six points with a single extra po
Bezzdna [24]
The team scored twenty-three points in total. 
This word sum can be worked out as follows:

Three field goals worth three points each is equal to nine points (3 x 3 = 9).
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Lastly, the team was awarded a bonus point for each touchdown they scored. They scored two touchdowns so they were awarded two extra points (2 x 1 = 2). 
Therefore, we have three subtotals: nine for the field goals; twelve for the touchdowns and two for the bonus points. The equation for this word sum is 9 + 12 + 2 = 23
3 0
4 years ago
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