All categories

3 years ago

Can I get help on 6&8 please?

Mathematics

1 answer:

Alika [10]3 years ago

6 0

8) 400 ÷ 36 = 11.111111..... So 12 shelves

You might be interested in

50 points! help, quick please!

kondor19780726 [428]

Answer:

Step-by-step explanation:

The two rules are :-

15 - 10(n - 1)

25 - 10n

6 0

3 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the

jeyben [28]

Answer:

Step-by-step explanation:

A) What is the speed of the pedestrian BC, CD, and DE?

Speed from B to C = distance/time = (40 - 20) / 4 = 20/4

= 5 km/h

Speed from C to D = distance/time = 0 / 2

= 0 km/h

Speed from D to E = distance/time = (20 - 0) / (10 - 6) = 20/4

= 5 km/h

B) After what time since the stop did he arrive at point E?

Since the stop at D, he arrived at E after (10 - 6) = 4 h

C) Write the formulas for function d(t) for sections BC, CD, and DE

For BC, d = 40 when t = 0 and d = 20 when t = 4

So d(t) = 40 - 5t

For CD, d = 20 when t = 4 and t = 6

So d(t) = 20

For DE, d = 20 when t = 6 and d = 0 when t = 10

So d(t) = 5 * (10 - t) or d(t) = 50 - 5t

4 0

3 years ago

Read 2 more answers

Use an area model to find the quotient: 132 ÷ 3 = ________.

7nadin3 [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Write an equation that describes each line in slope intercept form........slope= 4 y-intercept=-3

LenaWriter [7]

I’m pretty sure it’s y=4x-3

7 0

3 years ago

Read 2 more answers

Find the minimum cost of producing 60000 units of a product, where x is the number of units of labor, at $99 per unit, and y is

Y_Kistochka [10]

Answer:

The minimum cost of producing 60000 units of a product is $105867

Step-by-step explanation:

Since x is the number of units of labor, at $99 per unit, and y is the number of units of capital expended, at $84 per unit, The cost C(x,y) is given by:

$C(x, y) = 99x + 84y$

$P(x, y) = 100x^{0.25}y^{0.75}$

For the minimum cost:

$100x^{0.25}y^{0.75}=60000\\x^{0.25}(\frac{33x}{28} )^{0.75}=600\\x^{0.25}(\frac{33}{28} )^{0.75}x^{0.75}=600\\x^{0.25+0.75}*1.131=600$

Using the langrage multiplier,

$99=0.25(100)x^{-0.75}y^{0.75}\lambda...(1\\84=0.25(100)x^{0.25}y^{-0.25}\lambda...(2$

Dividing both equation 1 and 2

$y=\frac{33}{28}x$

Substituting $y=\frac{33}{28}x$ in $100x^{0.25}y^{0.75}=60000$ , we get:

$x_{min}=530.44$ labor units

Substituting $x_{min}=530.44$ labor units in $y=\frac{33}{28}x$ , we get

$y_{min}=\frac{33}{28}*530.44=625.16$ labor unit

$C(x, y) = 99x + 84y=99(530.44)+84(635.16) = $105867\\$

The minimum cost of producing 60000 units of a product is $105867

3 0

3 years ago