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OlgaM077 [116]
3 years ago
12

Which equation has the solutions x = (5 +- 2 \sqrt(7))/(3)?

Mathematics
2 answers:
asambeis [7]3 years ago
8 0
Recall the formula to find the solutions for an equation ax² + bx + c:
x₁₂ = (- b +/- √(b²-4ac) )/ 2a

Since at the denominator of our solution we have 3, which is an odd number, therefore it cannot be 2a, but only a, we should use the formula:

x₁₂ = <span>(-β +/- √(β²-ac) )/ a

Where </span>β = b/2

Hence, the only options that have an even number as b coefficient are C and D.

Now, we need to find what values give √(β² - ac) = 2√7 = √(4·7) = √28:

C) √(β² - ac) = √(25 - 3·6) = √7
D) √(β² - ac) = <span>√(25 - 3·(-1))</span> = √28

Hence, the correct answer is D) 3x² - 10x - 1 = 0
S_A_V [24]3 years ago
6 0

Answer:D

Step-by-step explanation:

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Step-by-step explanation:

I'll provide an example to help you. Let's say we were solving x^2+5x-7=0 and we wanted to factor the quadratic on the left side. We can't do that because the factors of -7 don't add up to 5. So we'd have to use the quadratic formula. The quadratic formula is essentially the last resort that will solve all quadratic equations, so it could be seen as a preferred method. But, unless you can factor the quadratic, it's much easier to solve.

Now let's do another one. x^2+5x+6=0 for example can be written as (x+2)(x+3)=0 and we can easily get x=-2 and x=-3 as solutions since plugging them into the factors would produce 0 (from the Zero Product Property). If we used the quadratic formula, it would take more time to plug in the variables and solve when we can just simply factor.

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Step-by-step explanation:

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3 years ago
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If a set of exam scores forms a symmetrical distribution, then the student mean scores is the median and the mode too.

<h3>What is a Symmetrical distribution?</h3>

A symmetrical distribution by definition is the situation which occurs when the values of variables appear at regular frequencies and is characterized by the mean, median, and mode all occuring at the same point in most cases.

Graphically, symmetrical distributions may appear as a normal distribution (i.e., bell curve).

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