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3 years ago

6

What is the mountain range know as the "backbone of England"

1 answer:

viktelen [127]3 years ago

5 0

The pennines was the backbone of England. Also called pennines hill.

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What is the name for the lowest layer of the atmosphere, which is most influenced by human activities?

MariettaO [177]

<span>Good Morning!

The atmospheric layer closest to us is the troposphere.

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3 years ago

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How do negative attitudes may hamper attempts to keep the environment clean and habitable to human beings

Reika [66]

Through engaging in improper activities, such as pollution and incorrect trash disposal, etc., a negative attitude may undermine efforts to keep the environment clean and hospitable for human beings.

<h3>What are the negative impact of the human towards the environment?</h3>

There are numerous ways in which people affect the environment like overpopulation, pollution burning fossil fuels, and deforestation and others.

The change in the climate due to global warming cause by the humans excessive heat produce by the factories which leave the poisonous gas into the environment.

Thus, Through engaging in improper activities, such as pollution and incorrect trash disposal, etc.

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11 months ago

PLEAS HELP ILL GIVE LOTS OF POINTS AND BRAINLYEST.<br><br> PLEAS ANSWER CORRECTLY.

hoa [83]

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Due to the impact of its cultural and political achievements during the 5th and 4th centuries BCE

Explanation:

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2 years ago

Which of the following articles was most likely written by a physical geographer, based on the titles? a. “Comparative Urban Env

Sauron [17]

The Answer to this question is "c"

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2 years ago

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What is the angular diameter in arc seconds of a star like the sun (diameter= 1,400,000 km) located 8 light years (7.57 x 10^13

ss7ja [257]

Answer:

$\theta = 0.0038\ arc\ sec$

option c

Explanation:

given data:

Diameter of a star = 1,400,000 km

star distance from sun $= 7.57\times 10^{13} km$

we know that

Angle is given as

$\theta = \frac{d}{r} = \frac{14\times 10^5}{7.57\times 10^{13}}$

$\theta = 1.849\times 10^{-8} rad$

we know that

$1\ arc\ second = 4.84\times 10^{-6} rad$

$1 rad = \frac{1\ arc\ sec}{4.84\times 10^{-6}}$

SO, $\theta = \frac{1.849\times10^{-8}}{4.84\times10^{-6}}$

$\theta = 3.82\time 10^{-3} arc sec$

$\theta = 0.0038\ arc\ sec$

option c

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2 years ago

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