All categories

3 years ago

Which ordered pair is the reflection of (5,-8) across the x axis and the y axis?

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

7 0

Answer:

(-5,8)

Step-by-step explanation:

Given : Point (5,-8)

To Find : Which ordered pair is the reflection of (5,-8) across the x axis and the y axis?

Solution :

The given point lies in 4th quadrant

The reflection of the point (x,y) across the x-axis is the point (x,-y).

Thus the reflection of (5,-8) is (5,8)

The reflection of the point (x,y) across the y-axis is the point (-x,y).

Thus the reflection of (5,-8) is (-5,8)

Hence (-5,8) ordered pair is the reflection of (5,-8) across the x axis and the y axis.

Lerok [7]3 years ago

3 0

The ordered pair would be (-5,8)

You might be interested in

Special Triangles

Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = $\frac{\sqrt{3} }{2}$ and tan30° = $\frac{1}{\sqrt{3} }$ , then

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{m}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

$\sqrt{3}$ × m = 12 ( divide both sides by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ ← rationalise by multiplying numerator/ denominator by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{12\sqrt{3} }{3}$ = 4 $\sqrt{3}$

-------------------------------------------------------------------------------

tan30° = $\frac{opposite}{adjacent}$ = $\frac{n}{6}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

$\sqrt{3}$ × n = 6 ( divide both sides by $\sqrt{3}$ )

n = $\frac{6}{\sqrt{3} }$ ← rationalise the denominator

n = $\frac{6}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{6\sqrt{3} }{3}$ = 2 $\sqrt{3}$

-----------------------------------------------------------------------------------

7 0

3 years ago

Is 0.3 greater that 0.15

valentina_108 [34]

Answer:

yes

Step-by-step explanation:

Simplifying then comparing both terms 0.3and 0.15, 0.3 is greater than

0.15, which means that the first term is greater than the second term.

8 0

3 years ago

Read 2 more answers

Which description of the vector shown is correct ?

BartSMP [9]

Answer:

(B) The magnitude is 7sqrt2, and the direction angle is approximately 135 degrees.

Step-by-step explanation:

From the figure, the coordinate of the tail of the vector,

$(x_1,y_1)=(3,-6).$

The coordinate of the head of the vector,

$(x_2,y_2)=(-4,1).$

The magnitude of a vector is the length between the head and tail of the vector.

By using the distance formula,

the magnitude of the vector $= \sqrt{(1-(-6))^2+(-4-3)^2}$

$=\sqrt{(7^2+(-7)^2}\\\\=\sqrt{98}\\\\=7\sqrt{2}$

Now, let $\theta$ be the angle made by the vector with the positive direction of the x-axis, so

$\tan\theta = \frac{y_2-y_1}{x_2-x_1}\\\\\Rightarrow \tan\theta = \frac{1-(-6)}{-4-3}=\frac{7}{-7}=-1 \\\\\Rightarrow \theta = \tan^{-1}(-1) \\\\\Rightarrow \theta =\pi- \tan^{-1}1 \\\\\Rightarrow \theta = \pi-\frac{\pi}{4} \\\\\Rightarrow \theta =\frac{3\pi}{4} \\\\\Rightarrow \theta = 135 ^{\circ}.$