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Ilia_Sergeevich [38]
3 years ago
15

What is 4x minus 7 factored​

Mathematics
1 answer:
dexar [7]3 years ago
4 0

Answer:

(

2

x

−

7

)

(

2

x

+

1

)

Step-by-step explanation:

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JulijaS [17]

Ans(a):

We know that a function can't have repeated x-values.

In given table we see that there i no repeating x-value. That's why the given table  represents function.


Ans(b):

We know that a function can't have repeated x-values.

So if in given table we see any repeating x-value then that may cause the given data set to not be a function.

like if we have 3, 4, 3, 11 in the input then it will not be a function.


Ans(c):

we can use two points say (3,5) and (4,7) to find the linear equation of the form y=mx+b

slope is given by

m=\frac{y_2-y_1}{x_2-x_1}=\frac{7-5}{4-3}=2

Noow plug value of m=2 and any point say (3,5) into y=mx+b

5=2(3)+b

5=6+b

-1=b

now plug m=2 and b=-1 in y=mx+b, we get y=2x-1

Hence required equation in function notation can be written as

f(x)=2x-1.


Now to prove that above function is correct, we just graph the given points from table and the obtained function.

We see that points lie on the grpah of f(x)=2x-1.

Which proves that our equation is correct.

4 0
3 years ago
Given that m=r-s/2nr
r-ruslan [8.4K]

Step-by-step explanation:

m =  \frac{r - s}{2nr}

m(2nr) = r-s

2×n×r×m = r-s

move the r on the right side to the left side

2nrm - r = -s

r ( 2nm - 1 ) = -s

r \:  =   \frac{ - s}{(2nm - 1)}

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3 years ago
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Answer:

x=-17

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3 years ago
Use the method of undetermined coefficients to solve the following differential equation: y′′+4y=4x
nikklg [1K]

Answer:

y(x) = C_1 cos 2 x + C_2 sin 2 x + x

Step-by-step explanation:

given,

y′′ + 4 y = 4 x

D² y + 4 y = 4 x

(D²+4) y = 4 x

now, writing Auxiliary  equation

m² + 4 = 0

m² = -4

m = ± 2 i

now, complimentary function

y_c = e^{ax}(C_1 cos b x + C_2 sin b x)

a = 0 ,  b = 2

y_c =C_1 cos 2 x + C_2 sin 2 x

particular integral (y_p)

y_p = a x

y'_p = a

y"_p = 0

now,

y′′+ 4 y = 4 x

0+ 4 (a x )= 4 x

4 a x = 4 x

     a = 1

now,

  y_p = x

now, general equation

y(x) = y_c + y_p

y(x) = C_1 cos 2 x + C_2 sin 2 x + x

 

4 0
3 years ago
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