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Ilia_Sergeevich [38]
3 years ago
15

What is 4x minus 7 factored​

Mathematics
1 answer:
dexar [7]3 years ago
4 0

Answer:

(

2

x

−

7

)

(

2

x

+

1

)

Step-by-step explanation:

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A.70<br> B.40<br> C.140<br> D.20
Nina [5.8K]
The question says that KN bisects JKL. This means that the angles are exactly equal. Thus, we can set the angles equal to each other to solve for x:

x + 30 = 3x - 50
30 = 2x - 50
80 = 2x
x = 40

Your answer is B. 40.
7 0
3 years ago
How do I write this in Point Slope, Slope-Intercept, and in Standard form. Thanks for the help!
AnnZ [28]
Point slope form: y - y1 = m (x - x1)
-------------------------------------------------

first you need to find the slope(m) by using the slope formula (seen below)

y2 - y1
m= ---------
x2 - x1


9 - 15
m= ---------
1 - (-2)


-6
m= --------- = -2
3

then choose either one of the coordinates you'd like and plug it in.

Im gonna use (-2, 15)

(y - 15) = -2 (x - (-2))
or
(y - 15) = -2 (x + 2)

slope intercept form: y = mx + b
-----------------------------------------------

you can use the slope formula to find that the slope(m) is -2

y = -2x + b

you can then plug in a coordinate to find b (the y-intercept)

I'll use (-2,15)

15 = -2(-2) +b
15 = 4 + b
-4 -4
---------
11 = b

in conclusion:

the slope(m) = -2

when (-2,15) is used
x = -2
y = 15
b = 11


standard form: ax + by = c
----------------------------------------

using the same coordinate (-2,15)


-2a + 15b = c
6 0
3 years ago
Help it’s algebra 2!! asap plzz
Ostrovityanka [42]
(x+3)(x-1/4)=x^2+11/4-3/4
3 0
3 years ago
For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.
andriy [413]

Answer:

If k = 1 or k = -\frac{1}{2}, there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

The signal of \bigtriangleup determines how many real roots an equation has:

\bigtriangleup > 0: Two real and different solutions

\bigtriangleup = 0: One real solution

\bigtriangleup < 0: No real solutions

In this problem, we have the following second order polynomial:

(k+1)x^{2} + 4kx + 2 = 0.

This means that a = k+1; b = 4k; c = 2

It has one solution if

\bigtriangleup = 0

b^{2} - 4ac = 0

16k^{2} -8(k+1) = 0

16k^{2} - 8k - 8 = 0

We can simplify by 8

2k^{2} - k - 1 = 0

The solution is:

k = 1 or k = -\frac{1}{2}

So, if k = 1 or k = -\frac{1}{2}, there is only one solution to the given quadratic equation.

4 0
3 years ago
What are the parts of an algebraic expression, and how do they relate to polynomial expressions?
Arlecino [84]

The parts of algebraic expressions related to polynomials are variables and coefficients.

<h3>What are the parts of algebraic expressions?</h3>

The parts of algebraic expressions are;

  • Variables which are letters that represent numbers
  • Coefficients are numbers that multiply the variables
  • Constant is a number that is not multiplied by any variable

Polynomials are algebraic expressions composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, and multiplication

Polynomials consists of variables and coefficients. The variables in polynomials are also called indeterminates. The coefficients also multiply this variables.

Thus, the parts of algebraic expressions related to polynomials are variables and coefficients.

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

3 0
2 years ago
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