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True [87]
3 years ago
15

412.638 in expanded form using fractions and decimals (5th)

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

i think its 400+10+2+.6+.03+0.008

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1/2 with an exponent of 4
Pani-rosa [81]
The answer is 0.0625
7 0
3 years ago
Read 2 more answers
Diego then says if we take half the first number and double the second the sum is 14. write an equation that could represent thi
Anon25 [30]

x = the first number

(x/2)² = 14

Hope this helps!

Can I get brainliest? thanks.

5 0
3 years ago
The National Center for Health Statistics, housed within the U.S. Centers for Disease Control and Prevention (CDC), tracks the n
Yakvenalex [24]

Answer:

a. 0.158

b. 0.01942

Step-by-step explanation:

For part a we define probability that the randomly selected person is if 65 years or more than that

a.

Probability of under age = 22.8% = 0.228

Probability of those from age 18 to 64 = 61.4% = 0.614

1-0.228-0.614

= 0.158

b.

P(uninsured) = p(those not up to 18) * p(those uninsured or under 18) + p(those age 18-64) * p(uninsured or under 18) + p(being 64plus) x P(uninsured or 64 plus)

= 0.228 x 0.051 + 0.614 x 0.124 + 0.158 x 0.011

= 0.011628 + 0.076136 + 0.001738

=0.089502

P(65 of older|uninsured) = p(64+) x P(uninsured or 64 plus)

= 0.157 x 0.011/0.089502

= 0.001738/0.089502

= 0.01942

4 0
3 years ago
Find the circumference of the circle. Use 3.14 for it. Round to the nearest hundredth, if necessary.
Marrrta [24]

Answer:

The circumference would be about 141.3 inches

Step-by-step explanation:

Place your radius into the formula for circumference (C=2πr)

<em>C = 2 × 3.14 × 22.5</em>

<em>C = 141.3</em>

8 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
4 years ago
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