Answer:
5v+35 = 5(v+7)
Step-by-step explanation:
5(v+7) = 5v+35
The answer is D :)))))))))
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
Answer:
Nein, du schlauer Penner
Step-by-step explanation:
You need to simplify it
lets start with your orgininal equation here:
-5+3x=10
Now lets try and get "x" alone. we will do this by adding 5 to both sides.
-5+3x=10
+5 +5
3x=15
Now we have 3 times "x" equals 15
The next step would be to divide both sides by 3 in order to get "x" alone.
3x=15
x=15/3
x=5