let's take a peek at the graph.
the graph of the equation touches the x-axis at 1, 2 and 3, at 1 it crosses it, at 2 it crosses it, at 3 is doesn't cross it, it simply bounces off of it.
on the roots/solutions the graph crosses the x-axis, they have ODD multiplicity, on the solutions it bounces off of it, they have EVEN multiplicity, so then.
x = 1 => x - 1 = 0 <------ one factor
x = 2 => x - 2 = 0 <------ another factor
x = 3 => x - 3 = 0 <------ another factor, BUT with even multiplicity
(x-1)¹(x-2)¹(x-3)² = f(x)
(x-1)(x-2)(x-3)² = f(x).
Answer:
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Step-by-step explanation:
snnaakaknananananabababababababababababa
nansskqlnzelsksuqqhnqqko
well, a negative plus a negative always will be a negative
example:
-1+-1=-2
Which of the following is the equation of a trend line for the scatter plot below? a. y = 3/2x + 1/2
The answer is 2,2 i already do the exam :D
