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mr Goodwill [35]
4 years ago
5

When one patient with a common cold takes a medicine and the other patient does not take any medicine the person who takes medic

ine recovers faster than the person who does not take medicine which of the following best to describe the situation
Mathematics
2 answers:
Kobotan [32]4 years ago
4 0
What options can you choose from? I guess it would be something like the medicine works or the medicine is not a placebo
pochemuha4 years ago
3 0
The one who takes the medicine heals faster then the one that does not take medicine takes a long time to get better
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Luke buys $14.35 worth of gasoline for his car. If the gas station $1.409 per gallon, how many gallons did he get? Round to the
iragen [17]

Answer:

10.2 gallons

Step-by-step explanation:

Luke buys $14.35 worth of gasoline for his car

The gas station sells at $1.409 per liter

Therefore the number of gallons that luke buys can be calculated as follows

= 14.35/1.409

= 10.2 gallons

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3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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