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34kurt
3 years ago
14

Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17

EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct?
Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0

Answer:

C. Both procedures are correct

e2020

MakcuM [25]3 years ago
4 0

Answer

They are both correct

Step-by-step explanation:

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7 0
1 year ago
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3 years ago
Brandon uses the steps below to solve the equation 15 x + 6 = 14 x + 5 using algebra tiles.
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7 0
3 years ago
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A napkin is folded into an isosceles triangle, triangle ABC, and placed on a plate, as shown. The napkin has a perimeter of 38 c
gavmur [86]
The area of plate which is covered by the napkin is equal to the area of folded napkin.

Before finding the area of folded napkin, we should find the dimension of the napkin.
Find the length of the leg side, the two leg has similar length.
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l + l + 8 = 38
2l + 8 = 38
2l = 30
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Each leg is 15 cm long.

Find the area of folded napkin
area = 1/2 × s × s × sin of angle between the sides
area = 1/2 × 15 × 15 × sin 30°
area = 1/2 × 15 × 15 × 1/2
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area = 56.25
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The answer is third option
6 0
3 years ago
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