Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17 EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct?
2 answers:
Answer:
C. Both procedures are correct
e2020
Answer
They are both correct
Step-by-step explanation:
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<span>d)Segment AC and segment CB are equal in measure.
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9514 1404 393
Answer:
?° = 153°
Step-by-step explanation:
The measure of an arc is the same as the measure of the central angle it subtends. The arc is marked 153°. The central angle (?°) has that same measure.
?° = 153°
Answer:
1.= Correct
2.= False(Raul has a negative slope and Becky has a positive, it is not both positive so FALSE)
3.= Corect(They both cross on the x and y axis.)
Step-by-step explanation:
