64/9 in a mixed number

Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18.<br><br> (see the image)

hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

$(x-y)^2+10wz$

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

$=(25-10)^2+10(11)(18)$

First, subtract within the parentheses:

$=(15)^2+10(11)(18)$

Square 15:

$=225+10(11)(18)$

Now, multiply the terms on the right. 10 times 11 is 110:

$=225+110(18)$

Multiply:

$=225+1980$

Finally, add:

$=2205$

So, our answer is D.

And we're done!

8 0

3 years ago

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15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000 (9/8)^x represents t

Ainat [17]

I'm guessing you mean f(x)=15,000(9/8)^x. If this is what you mean, the population would increase by about 12,000 (12030.4870605 to be exact).
Step-by-step explanation:
Starting equation: f(x)=15,000(9/8)^x
You can clean up the 9/8 to be 1.125
Now what you want to do is find the answer to (9/8)^5 which is 1.8020324707
Next multiply 1.8020324707 by 15,000 and you get 27030.4870605
Finally 27,030.4870605 - 15,000 gives you 12030.4870605. Which means that the population increased by about 12,000.

Please mark me brainiest cuz I need one more to level up!! Thank you

5 0

2 years ago

What is the radius of a circle in which a 30° arc is 2 inches long?

marysya [2.9K]

It would be 1 inch and 15 degree arc due to the act that the radius is half.

5 0

3 years ago

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A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

1 year ago

Classify triangle ABC by its sides if side AB = 6x, side AC = 4x + 6 and side BC = 8x + 3. The perimeter of triangle ABC is 63.

sladkih [1.3K]

6x + 4x+6 + 8x+3 = 63
6x+4x+8x = 63 - 3 - 6
18x = 54
x = 54/18
x = 3

Side AB = 6(3) = 18
Side AC = 4(3)+6 = 18
Side BC = 8(3)+3 = 27

3 0

3 years ago

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