Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
24 ?
Step-by-step explanation:
50% or .5%?
12*2 = 24
Answer:
He earned 110287.3536 dollars
Answer:
Only option d is not true
Step-by-step explanation:
Given are four statements about standard errors and we have to find which is not true.
A. The standard error measures, roughly, the average difference between the statistic and the population parameter.
-- True because population parameter is mean and the statistic are the items. Hence the differences average would be std error.
B. The standard error is the estimated standard deviation of the sampling distribution for the statistic.
-- True the sample statistic follows a distribution with standard error as std deviation
C. The standard error can never be a negative number. -- True because we consider only positive square root of variance as std error
D. The standard error increases as the sample size(s) increases
-- False. Std error is inversely proportional to square root of n. So when n decreases std error increases
Answer:
6523
Step-by-step explanation:
I'm assuming that the question is asking us to rearrange the numbers 5,3,2,6 to obtain the largest possible value that is odd.
In order for a number to have the largest value, the first digit of the number must he the largest possible value. In this case, we see that the largest value is 6, hence the number must begin with 6 i.e 6XXX
We can do the same for the next digit in the hundreds position by picking the largest possible remaining number. In this case, it is the number 5. So the number will look something like this: 65XX
We see that the only remaining numbers are 3 and 2.
Recall that for a number to be odd, the digit on the ones place must also be odd. Of the remaining numbers, only 3 is odd, hence the last number must be 3. i.e 65X3
Hence the last remaining number is 2
6523
