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konstantin123 [22]
3 years ago
12

A rectangular sandbox has a width of 5 feet the sandbox is five times as long as it's with what is the perimeter of the sandbox

Mathematics
1 answer:
seraphim [82]3 years ago
5 0
5 feet wide and it's
25 feet long
perimeter = 2*5 + 2*25 = 60 feet


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3. Simplify.<br><br> 312⋅312 <br><br> 4. Rewrite n√xm<br><br> using a rational expression.
Dmitry_Shevchenko [17]

Answer:


Step-by-step explanation:

Left

As near as I can tell, the question is x^(1/2) * x^(1/2) = The bases are the same, so all you do is add the powers.

x^(1/2 + 1/2) = x^1 which is just x.

Right

The is another one where the work is hard to show. The numerator (m) of the fraction is the power and the denominator (n) is the root. That sentence is all the work there is.

So you would write \sqrt[m]{x^{n} } = x^{\frac{m}{n} }


6 0
3 years ago
Read 2 more answers
Find the equation of a line parallel to 2x-3y+6=0, with the same y-intercept as y=7x-1
shepuryov [24]
The answer is y=2/3x -1
5 0
3 years ago
What is the equation of this graph? Please answer this I am soo stuck.
OLEGan [10]

Answer:

y = 8x + 50

Step-by-step explanation:

Use (0,50) and (10,130)

Slope: m = (130-50)/(10-0) = 8

Y-intercept is 50

y = 8x + 50

3 0
3 years ago
Someone please answer this correctly!!
Luda [366]

Answer:

1.98 × 10^10

Step-by-step explanation:

First solve for how many text messages were sent out per one month:

22,000,000 × 900

19,800,000,000

Convert into scientific notation:

1.98 × 10^10

In scientific notation, there can only be one number before the decimal. The rest of the numbers must be after the decimal; hence, why I put the numbers 9 and 8 after the decimal. If the rest of the numbers are zeros, you do not have to add them after the decimal. Instead, starting from right to left, count the number places until you reach your decimal. The number you have counted will be your exponent. I counted nine 0's, one 8, and one 9 which made this exponent 10 as there were 10 decimal placements.

6 0
3 years ago
Send it quick guys...
Paladinen [302]

Answer:

194

Step-by-step explanation:

Recall 2 rules to solve this easily:

1. (a+b)^2=a^2+2ab+b^2

2. (a-b)^2=a^2-2ab+b^2

<em>Now, if we let a = 7  and  b=4\sqrt{3}, we can say the problem is basically of the form:</em>

(a+b)^2 + (a-b)^2

This can be simplified using the rules:

(a+b)^2 + (a-b)^2\\a^2+2ab+b^2+a^2-2ab+b^2\\2a^2+2b^2

Now we can plug the values of a and b we initially thought of (remember though  \sqrt{x} \sqrt{x} =x):

2a^2+2b^2\\2(7)^2+2(4\sqrt{3})^2\\ 2(49)+2(4\sqrt{3})(4\sqrt{3})\\98+2(4)(4)(\sqrt{3} )(\sqrt{3} )\\98+2(4)(4)(3)\\98+96 \\194

194 is the final answer.

7 0
4 years ago
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