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3 years ago

Name the three sides of the triangle

Mathematics

1 answer:

frutty [35]3 years ago

3 0

Answer: Equilateral, Isosceles and Scalene

right triangle, with the side opposite the right angle being termed the hypotenuse and the other two sides being known as the legs.

hope this helped (sorry if its confusing)

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Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the

beks73 [17]

In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: $m= \frac{P( \frac{r}{12}) }{1-(1+ \frac{r}{12})^{-12t} }$
where
$m$ is the monthly payment
$P$ is the amount
$r$ is the interest rate in decimal form
$t$ is the number years

First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
$\frac{4}{100} =0.04$
We also know from our question that $P=224500$ and $t=30$ , so lets replace those values into our formula to find the monthly payment:
$m= \frac{224500( \frac{0.04}{12}) }{1-(1+ \frac{0.04}{12})^{-(12)(30)} }$
$m=1071.80$

We can conclude that the monthly payment during the initial period is $1071.58<span />

7 0

3 years ago

Need help!!!!!! Very much stuck!

vovikov84 [41]

Give the guy above Brainly and me just a like he is correct

4 0

3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago

For how many games Is the total cost of bowling equal for the two bowling establishments? Family Bowling- Game $4 Shoes $1 Knigh

skad [1K]

Step-by-step explanation:

Answer: If you play 4 games, the price will be the same in the two establishments.

Step-by-step explanation:

Ok, in Family Bowling we have:

$4 per game, plus $1 per shoes (the shoes are paid only one time).

Then, the price for X games, is:

Pa(X) = $4*X + $1.

In Knight Owl Bowling we have:

$3.75 per game and $2 for the shoes, the price for X games will be:

Pb(X) = $3.75*X + $2.

Now, if we want to pay the same in both establishments, we have:

Pa(X) = Pb(x)

$4*X + $1 = $3.75*X + $2

Now we should solve this for X.

$4*X - $3.75*X = $2 - $1 = $1

($4 - $3.75)*X = $1

$0.25*X = $1

X = $1/$0.25 = 4.

If you play 4 games, the price will be the same in the two establishments.

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