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zavuch27 [327]
3 years ago
11

How dos the respitory system help build social relationships?

Advanced Placement (AP)
2 answers:
Anestetic [448]3 years ago
7 0
The respiratory system plays are crucial role into the socialization of the humans. Apart from being the system that enables us to breath, it is also the system that enables us to generate sounds, to speak. The humans have vocal chords, and they are part of this system, and as they create vibrations, the respiratory systems delivers them to our mouths where the final product of the sound is released, thus we are able to speak and communicate with each other.

Read more on Brainly.com - brainly.com/question/2376804#readmore
Tom [10]3 years ago
5 0

Answer:

The respiratory system helps create sound that enables humans to communicate with each another. The respiratory system helps prevent the spread of disease so humans are able to live in communities together

Explanation:

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Help with Question 16- not sure of the answer
vivado [14]

Answer:

llevaron

Explanation:

The question here  is past tense, in the phrase "Cuando yo era joven"

which equates to "when I was young" - the object being described is "mis padres", so llevaron is the correct conjugation using past tense.

6 0
2 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
2 years ago
Bryan takes out an unsubsidized loan of $3,000 with an interest rate of 5%/per year. How much will he owe at time of graduation?
Deffense [45]

Answer:

Explanation:

C

5%3000 = 150

150 x 4 = 600

3000 + 600 = 3600

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2 years ago
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