$\therefore \: AO \: \cong \: CO.. (given) \\ \\ \: \: \: \: \angle \: AOB \: \cong \:\angle \:COD\\..(vertically\:opposite\:angles) \: \\ \\ \& \: \: \: BO \: \cong \: DO.. (given) \\ \\ \therefore \triangle \: AOB \: \cong \: \triangle \:COD \\ ..(by \: SAS \: test \: of \: congruence ) \\ \\ \therefore AB = CD.. \\ (Corresponding \: sides \: of \: congruent \: triangles)$

8 0

3 years ago

Help x^2+10x=24 solve and simplify

IRINA_888 [86]

Answer:

x= 2, x= -12

Step-by-step explanation:

cuz i said so

first move the 24 to the other side of the equation by subtracting it from both side's

now the equation looks like this

x^2+10x-24

then find values that add to equal 10 and that also multiply to equal -24

this works out to (x-2) (x+12)

which means that x is equal to 2 and -12

6 0

2 years ago