Which point could be on the line that is perpendicular to MN and passes through point k

Mathematics

2 answers:

balandron [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Is there supposed to be a picture? Need more info.

Scilla [17]3 years ago

3 0

The answer to this question is C. (2,2). There's no picture, but I think I know which question this is.

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Consider the given functions.

polet [3.4K]

Answer:

I'm pretty sure it is c

Step-by-step explanation:

3 0

3 years ago

732,178 + 167 - 542,137

Bezzdna [24]

Answer:

190,208

Step-by-step explanation:

732,178 + 167 = 732345

732345 - 542,137 = 190,208

6 0

3 years ago

Read 2 more answers

I NEED HELP ON THIS PROBLEM!!! PLEASE

Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well then, so since this equation has that slope therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}$

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

$(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})$