Answer:
frequency of homozygous recessive = q² = 0.16
the predicted frequency of heterozygotes = 2pq = 2 × 0.4 × 0.6 = 0.48
the predicted frequency of homozygous dominant = p² = 0.6² = 0.36
Explanation:
Given that:
Number of recessive homozygous survivors = 16
Total number of population survivors = 100
Predicted frequency of homozygous recessive individuals (q²) = 16/100 = 0.16
Frequency of recessive allele (q) = √0.16 = 0.4
p + q = 1
∴ p = 1 - q = 1 - 0.4 = 0.6
Frequency of dominant allele (p) = 0.6
frequency of homozygous recessive = q² = 0.16
the predicted frequency of heterozygotes = 2pq = 2 × 0.4 × 0.6 = 0.48
the predicted frequency of homozygous dominant = p² = 0.6² = 0.36
p² + q² + 2pq = 1
0.16 + 0.36 + 0.48 = 1 (proved)
The reduction in population due to some event in the original gene is no longer in the surviving population. Since the population is now small, there is likely to be genetic drift.
The flash flood caused change in allele frequency leading to a micro evolution.
