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sineoko [7]
3 years ago
12

Sort these words with the correct definition. Words: Theme, Convey, Poem, & Stanza.

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0

Answer: convey- make an idea understandable; theme- subject or topic; poem- writing in speech and song, with stanzas; stanza- group of lines, verse

Step-by-step explanation:

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Can someone explain how I multiply both sides ?
stellarik [79]

Answer:

x=3

Step-by-step explanation:

Given,

1 = 1/(x-2)

Multiply both sides by (x-2),

1*(x-2) = 1/(x-2) * (x-2)

x-2 = 1

Adding 2 on both sides,

x-2+2 = 1+2

x = 3

6 0
2 years ago
The total cost of attending a state university is $19,700 for the first year. • A student's grandparents will pay half of this c
Temka [501]

Answer:

The student will have to save $404.2 minimum monthly

Step-by-step explanation:

Given that the total cost for the first year= $19,700

The grandparents paid half the amount = 1/2(19700)= $9850

The remaining balance to be paid is

19,700 - 9850=$9850

If an athlete paid $5000

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Hence the minimum amount to be saved per month is $404.2

4 0
3 years ago
Read 2 more answers
Mrs. Hilt bought 15 books. Sh paid $11 for each book. She later sold all 15 books for $25 each. What is the difference between t
sweet [91]
Total amount of money paid
=11 x 15
=$165

total amount of money sold
=25 x 15
=$375

difference
= 375 - 165
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4 0
3 years ago
O is the origin, OP = p and OQ = q.
vaieri [72.5K]

Answer:

its c

Step-by-step explanation:

got it correct

5 0
3 years ago
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed i
Hunter-Best [27]

Answer:

a)  σ/√n= 1.43 min

c) Margin of error 2.8028min

d) [30.1972; 35.8028]min

e) n=62 customers

Step-by-step explanation:

Hello!

The variable of interest is

X: Time a customer stays at a restaurant. (min)

A sample of 49 lunch customers was taken at a restaurant obtaining

X[bar]= 33 mi

The population standard deviation is known to be δ= 10min

a) and b)

There is no information about the distribution of the population, but we know that if the sample is large enough, n≥30, we can apply the central limit theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

Where μ is the population mean and σ²/n is the population variance of the sampling distribution.

The standard deviation of the mean is the square root of its variance:

√(σ²/n)= σ/√n= 10/√49= 10/7= 1.428≅ 1.43min

c)

The CI for the population mean has the general structure "Point estimator" ± "Margin of error"

Considering that we approximated the sampling distribution to normal and the standard deviation is known, the statistic to use to estimate the population mean is Z= (X[bar]-μ)/(σ/√n)≈N(0;1)

The formula for the interval is:

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

The margin of error of the 95% interval is:

Z_{1-\alpha /2}= Z_{1-0.025}= Z_{0.975}= 1.96

d= Z_{1-\alpha /2}*(σ/√n)= 1.96* 1.43= 2.8028

d)

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

[33±2.8028]

[30.1972; 35.8028]min

Using a confidence level of 95% you'd expect that the interval [30.1972; 35.8028]min contains the true average of time the customers spend at the restaurant.

e)

Considering the margin of error d=2.5min and the confidence level 95% you have to calculate the corresponding sample size to estimate the population mean. To do so you have to clear the value of n from the expression:

d= Z_{1-\alpha /2}*(σ/√n)

\frac{d}{Z_{1-\alpha /2}}= σ/√n

√n*(\frac{d}{Z_{1-\alpha /2}})= σ

√n= σ* (\frac{Z_{1-\alpha /2}}{d})

n=( σ* (\frac{Z_{1-\alpha /2}}{d}))²

n= (10*\frac{1.96}{2.5})²= 61.47≅ 62 customers

I hope this helps!

3 0
3 years ago
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