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4 years ago

What is the volume of a right circular cylinder with a radius of 4 M and a height of 4 meters

Mathematics

2 answers:

beks73 [17]4 years ago

7 0

Answer:

64 $\pi$ $m^{3}$

gregori [183]4 years ago

3 0

Answer:

V = 200.96 m^3

Step-by-step explanation:

The volume of a cylinder is

V = pi r^2 h where r is the radius and h is the height

V = pi (4)^2 *4

V = 64 pi m^3

If we approximate pi as 3.14

V = 200.96 m^3

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3 years ago

A circle has a diameter of 25cm. How far from the centre of this circle is a chord 16cm long? Draw a picture before you start.

yan [13]

Answer:

The cord is 9.6 cm away from the centre of the circle.

Step-by-step explanation:

See The Image First

The image below shows a picture of everything that’s given, labeled, and drawn in the circle.

Description of the Picture:

You can use the Pythagorean to find the what the distance (the length b) the cord is from the center. You can use the radius as the hypotenuse. The radius is half of the diameter, and the diameter is 25. So the radius is 12.5, which means that 12.5 is the hypotenuse of the triangle (also known as side c). The whole length of the cord is 16cm long, and we can use half of the cord, which is 8cm, for the triangle. So we know two sides already: the hypotenuse (the radius) and the length a of the triangle (half of the length of the cord).

To Solve (variables a, b, and c, are in italics so you don’t get confused):

⇒ Use the formula of the Pythagorean Theorem ( $a^{2}+b^{2}=c^{2}$ ), where b is the length of the distance from the cord to the centre of the circle (what we need to find out), a is the length of the side of the triangle (half of the cord size – 8cm), and c is the hypotenuse (the radius – 12.5cm). So plug the given values of b and c into the formula:

$a^{2}+8^{2}=12.5^{2}$

⇒ Solve for a by simplify:

$a^{2}+64=156.25$

⇒ Subtract 64 from both sides:

$a^{2}=92.25$

⇒ Find the square root of both sides to get a by itself:

$\sqrt{a^{2}}=\sqrt{92.25}$

⇒ Simplify to get:

$a=\sqrt{92.25}$ which convert’s to $a=9.60468635...$ round the answer to the nearest tenth is $a=9.6$

Answer: The cord is 9.6 cm away from the centre of the circle.

I hope you understand and that this helps with your question! :)

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3 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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3 years ago

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What is the volume of a right circular cylinder with a radius of 4 M and a height of 4 meters​

What is the volume of a right circular cylinder with a radius of 4 M and a height of 4 meters