I got 18. i did this by using the SOH CAH TOA method. In this case you have the the angle and the hypotenuse, and you’re looking for the adjacent side, therefore you need to use CAH
Number one : x^6 yz^8
number two : 64x^6 z^12 / y^9
number three : x^9 y^3
number four : y^7/x^7z^3
number five : x^3/5y^2
number six : x^12y^3/z^6
The point 6 cm away from the center travels in a circle of circumference 2π*(6 cm) = 12π cm, so that it covers this distance per revolution, 12π cm/1 rev.
So the disk has a linear speed of
(6000 rev/min) * (12π cm/rev) = 72,000π cm/min
which is equivalent to
(72,000π cm/min) * (1/100,000 km/cm) * (60 min/h)
or approximately 135.7 km/h.
Answer:
(2x+1)(5x+3)
Step-by-step explanation:
'split the x-term and factorise by grouping
10x2+5x+6x+3←(5x+6x=11x)
5x(2x+1)+3(2x+1)
factor out (2x+1)
(2x+1)(5x+3)
⇒10x2+11x+3=(2x+1)(5x+3)
plz mark me as brainliest if this helped :)