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Sergeeva-Olga [200]
4 years ago
10

By applying styles,____ formats are being applied each time?

Computers and Technology
1 answer:
Ray Of Light [21]4 years ago
8 0
(A) the same, by applying styles the same formats are being applied each time.
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Gaven's instructor told him to include a personal statement in his work portfolio. Why did his instructor recommend including a
algol [13]
The recommendation of the instructor for Gaven to include a personal statement in his work portfolio will allow him to identify his career goals. If he is unable to show this to his work portfolio then he may simply state it in the personal statement. Thus, the answer to this item is letter A. 
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3 years ago
Is discord down right now?
Eva8 [605]

Answer:

yes it is

Explanation:

To do this, visit discord.com and login to the web version. Once logged in using the right credentials launch the app on your PC, discord should work properly now. Ensure the system is up to date. As a last resort, uninstall and reinstall the app again.

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When a piece of shiny silver jewelry gets tarnished, what has happened?
makvit [3.9K]
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6 0
3 years ago
Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, a
Viktor [21]

Answer:

The program to this question can be given as:

Program:

import java.util.*;

//import package for user input  

class Main     //define class

{

public static void main(String a[])  

//define main function

{

int positive_number=0,negative_number=0,count=0,num; //define variable

double total=0,avg=0;  

//creating Scanner class object.

Scanner ob = new Scanner(System.in);

System.out.println("Enter an integer, when done input 0: "); //message

num= ob.nextInt();

//taking input from user

if (num==0)  //check number equal to 0  

{  

System.out.println("No numbers are entered except 0"); //message

System.exit(1);

}

else

{

while (num!= 0)  

{    

   if (num> 0)

   {

positive_number++; // Increase positives

}

else

{

negative_number++; // Increase negatives

}

total=total+num; // Accumulate total

count++;    // Increase the count

num=ob.nextInt();

}

// Calculate the average

avg=total/count;

// Display values

System.out.println("The positive number is:"+positive_number);

System.out.println("The negatives number is:"+negative_number);

System.out.println("total is:"+total);

System.out.println("average is:"+avg);

}

}

}

Output:

Enter an integer, when done input 0: 22

2

1

4

0

The positive number is:4

The negatives number is:0

total is:29.0

average is:7.25

Explanation:

In the above program firstly we import the package for user input then we define a class that is main in this class we define the main method in the main method we define variable. Then we create a scanner class object for user input. In the number variable, we take multiple inputs from the user and also check that the user does not insert 0 at the starting of the program. To check this we use the condition statement that is a number equal to 0 then it will terminate the program. In the else part we first declare the loop that checks that inserted number is positive and negative and in this, we calculate the total of the numbers and at the end of the loop, we calculate the average of the number and print all the values.

4 0
3 years ago
Read 2 more answers
Define a class called TreeNode containing three data fields: element, left and right. The element is a generic type. Create cons
m_a_m_a [10]

Answer:

See explaination

Explanation:

// Class for BinarySearchTreeNode

class TreeNode

{

// To store key value

public int key;

// To point to left child

public TreeNode left;

// To point to right child

public TreeNode right;

// Default constructor to initialize instance variables

public TreeNode(int key)

{

this.key = key;

left = null;

right = null;

key = 0;

}// End of default constructor

}// End of class

// Defines a class to crate binary tree

class BinaryTree

{

// Creates root node

TreeNode root;

int numberElement;

// Default constructor to initialize root

public BinaryTree()

{

this.root = null;

numberElement = 0;

}// End of default constructor

// Method to insert key

public void insert(int key)

{

// Creates a node using parameterized constructor

TreeNode newNode = new TreeNode(key);

numberElement++;

// Checks if root is null then this node is the first node

if(root == null)

{

// root is pointing to new node

root = newNode;

return;

}// End of if condition

// Otherwise at least one node available

// Declares current node points to root

TreeNode currentNode = root;

// Declares parent node assigns null

TreeNode parentNode = null;

// Loops till node inserted

while(true)

{

// Parent node points to current node

parentNode = currentNode;

// Checks if parameter key is less than the current node key

if(key < currentNode.key)

{

// Current node points to current node left

currentNode = currentNode.left;

// Checks if current node is null

if(currentNode == null)

{

// Parent node left points to new node

parentNode.left = newNode;

return;

}// End of inner if condition

}// End of outer if condition

// Otherwise parameter key is greater than the current node key

else

{

// Current node points to current node right

currentNode = currentNode.right;

// Checks if current node is null

if(currentNode == null)

{

// Parent node right points to new node

parentNode.right = newNode;

return;

}// End of inner if condition

}// End of outer if condition

}// End of while

}// End of method

// Method to check tree is balanced or not

private int checkBalance(TreeNode currentNode)

{

// Checks if current node is null then return 0 for balanced

if (currentNode == null)

return 0;

// Recursively calls the method with left child and

// stores the return value as height of left sub tree

int leftSubtreeHeight = checkBalance(currentNode.left);

// Checks if left sub tree height is -1 then return -1

// for not balanced

if (leftSubtreeHeight == -1)

return -1;

// Recursively calls the method with right child and

// stores the return value as height of right sub tree

int rightSubtreeHeight = checkBalance(currentNode.right);

// Checks if right sub tree height is -1 then return -1

// for not balanced

if (rightSubtreeHeight == -1) return -1;

// Checks if left and right sub tree difference is greater than 1

// then return -1 for not balanced

if (Math.abs(leftSubtreeHeight - rightSubtreeHeight) > 1)

return -1;

// Returns the maximum value of left and right subtree plus one

return (Math.max(leftSubtreeHeight, rightSubtreeHeight) + 1);

}// End of method

// Method to calls the check balance method

// returns false for not balanced if check balance method returns -1

// otherwise return true for balanced

public boolean balanceCheck()

{

// Calls the method to check balance

// Returns false for not balanced if method returns -1

if (checkBalance(root) == -1)

return false;

// Otherwise returns true

return true;

}//End of method

// Method for In Order traversal

public void inorder()

{

inorder(root);

}//End of method

// Method for In Order traversal recursively

private void inorder(TreeNode root)

{

// Checks if root is not null

if (root != null)

{

// Recursively calls the method with left child

inorder(root.left);

// Displays current node value

System.out.print(root.key + " ");

// Recursively calls the method with right child

inorder(root.right);

}// End of if condition

}// End of method

}// End of class BinaryTree

// Driver class definition

class BalancedBinaryTreeCheck

{

// main method definition

public static void main(String args[])

{

// Creates an object of class BinaryTree

BinaryTree treeOne = new BinaryTree();

// Calls the method to insert node

treeOne.insert(1);

treeOne.insert(2);

treeOne.insert(3);

treeOne.insert(4);

treeOne.insert(5);

treeOne.insert(8);

// Calls the method to display in order traversal

System.out.print("\n In order traversal of Tree One: ");

treeOne.inorder();

if (treeOne.balanceCheck())

System.out.println("\n Tree One is balanced");

else

System.out.println("\n Tree One is not balanced");

BinaryTree

BinaryTree treeTwo = new BinaryTree();

treeTwo.insert(10);

treeTwo.insert(18);

treeTwo.insert(8);

treeTwo.insert(14);

treeTwo.insert(25);

treeTwo.insert(9);

treeTwo.insert(5);

System.out.print("\n\n In order traversal of Tree Two: ");

treeTwo.inorder();

if (treeTwo.balanceCheck())

System.out.println("\n Tree Two is balanced");

else

System.out.println("\n Tree Two is not balanced");

}// End of main method

}// End of driver class

5 0
4 years ago
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