Question

(3)-2 Evaluate exponent

Answer 1

Answer:

$3^{-2} = \dfrac{1}{9}$

Step-by-step explanation:

Definition of negative exponent:

$a^{-n} = \dfrac{1}{a^n}$

In our case, a = 3 and -n = -2.

$3^{-2} = \dfrac{1}{3^2}$

Now we just evaluate the power in the denominator.

$3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}$