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3 years ago

(3)-2 Evaluate exponent

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

$3^{-2} = \dfrac{1}{9}$

Step-by-step explanation:

Definition of negative exponent:

$a^{-n} = \dfrac{1}{a^n}$

In our case, a = 3 and -n = -2.

$3^{-2} = \dfrac{1}{3^2}$

Now we just evaluate the power in the denominator.

$3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}$

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PLEASE HELP!!! I’m very confused haha

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The person that factored the polynomial did one thing wrong -- they used minus signs when they should've used plus signs. We can figure this out because of the values of the quantities in the original trinomial. Since all of them are positive, we know that either there are two plus signs or that there is a minus and a plus sign with the value to the right of the plus sign being greater than the value to the right of the minus sign. But, that wouldn't work here, so the only thing wrong with this answer is that the plus signs should be minus signs.

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3 years ago

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Which of the following sets shows all the numbers from the set {1, 2.5, 3, 4.5, 5} that make the inequality 3a + 4 ≥ 13 true?

zmey [24]

3(1)+4≥ 13
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3(2.5)+4≥ 13
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3 years ago

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One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe

sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

n = sample of respondents = 2625

p = population proportion of people who disagree with statement

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ , $0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ ]