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Pie
3 years ago
11

(3)-2 Evaluate exponent

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

3^{-2} = \dfrac{1}{9}

Step-by-step explanation:

Definition of negative exponent:

a^{-n} = \dfrac{1}{a^n}

In our case, a = 3 and -n = -2.

3^{-2} = \dfrac{1}{3^2}

Now we just evaluate the power in the denominator.

3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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3 years ago
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

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So replace -a with -6a+5a in the expression we started with

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now we factor by grouping

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ANSWER 20%
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