Answer:
#2 is a ratio so you gotta add.
#3 it’s just adding it for example 2p + 5a = 7pa
Using an exponential function, it is found that the approximate number of crimes in the year of 2016 was of 2502.
<h3>What is an exponential function?</h3>
An increasing exponential function is modeled by:

In which:
- A(0) is the initial value.
- r is the growth rate, as a decimal.
In this problem, there were 550 crimes in the initial year observed, and the growth rate is of 6%, hence the parameters are A(0) = 550, r = 0.06, and the equation is given by:



2016 is 26 years after 1990, hence:

The approximate number of crimes in the year of 2016 was of 2502.
More can be learned about exponential functions at brainly.com/question/25537936
Condimentando ENCANTÁNDOSELA SUSTENTADOR
So this is just working with exponents, but negative exponents can be a little tricky. your example didn't do a great job of showing how you calculate negative exponents.
for #2, you have 10⁻⁶
to convert negative exponents into something that makes more sense to our brain, you can set it beneath 1:

... or, in the event that you can't see that because you're on the app: (1)/(10⁶). so now, instead of calculating 10⁻⁶, which would probably give you a confusing decimal, you just need to figure out 10⁶ -- and positive exponents are much easier to deal with.
10⁶ = 1,000,000
BUT remember that you have to put this value beneath a 1 to account for your negative exponent and (1/1,000,000) is your answer for part A.
so, use the same steps for the rest of the problems:
1) convert negative exponent to positive exponent beneath 17⁻³ = (1)/(7³)
2) calculate 7³7³ = 343
<span>
3) your result is (1/343)</span>
<span>for 12</span>⁻², again, you'll put it beneath 1 so that it becomes (1)/(12²), then you'll calculate 12² (12*12 = 144), so that your result is (1/144). that leaves the letter D for number 2, which you'll have to write into your boxes at the top.
i hope this helps! you can message me if you have any specific ones that cause you trouble and i'll do my best to help.