Complete question :
Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of shampoo. 70L+ 60S < 5600 represents the number of long-haired members L and short-haired members S who can wash their hair with less than 5600 liters of water. 0.02L + 0.01S < or equal to 2.5 represents the number of long-haired members and short-haired members who can wash their hair with at most 2.5 liters of shampoo. Does the bathroom have enough water and shampoo for 8 long-haired members and 7 short -haired members?
Answer:
Yes , there is enough water and shampoo
Step-by-step explanation:
Given that:
Number of long and short hair member who can wash their hair with less than 5600 litres of water.
70L+ 60S < 5600
Number of long and short hair member who can wash their hair with at most 2.5 litres of shampoo
0.02L + 0.01S ≤ 2.5
To check if bathroom has enough water and shampoo for 8 long haired and 7 short haired members.
Water check:
70L+ 60S < 5600
L = 8 ; S = 7
70(8) + 60(7) < 5600
560 + 420 < 5600
980 < 5600
Inequality constraint is satisfied ; There is enough water.
Shampoo check:
0.02L + 0.01S ≤ 2.5
L = 8 ; S = 7
0.02(8) + 0.01(7) ≤ 2.5
0.16 + 0.07 ≤ 2.5
0.23 ≤ 2.5
Inequality constraint is satisfied ; There is enough shampoo
Answer:
the higher the magnitude, the the lower the frequency.
The answer is D. The law of detachment states that
"If P than Q. P."
In this case passing the bar exam is P and getting to practice law is Q. So if we know that Candice is allowed to practice law if she passes the bar exam and that she did pass the exam. The conclusion that Candice can now practice law is valid.
-1 - (-7) = 6
5 - (-1) = 6
11 - 5 = 6
The common difference is 6.
If you add 6 to a term, you get the next term.
30 + 2 = 32
