All categories

3 years ago

Plzz help thank you!!!

Mathematics

2 answers:

Stolb23 [73]3 years ago

7 0

I think the answer would be 78 ... I could be wrong tho

stepan [7]3 years ago

4 0

Answer:120

Step-by-step explanation:

find the pathogorious relationship of 5,12,13

the formulae is 1/2bh

1/2*5*12=30

multiply 3 and 4 because there are 4 triangles in the rhombus

You might be interested in

Please answer 6 and 7

sleet_krkn [62]

Answer:

ok aaj SGD Hv the best of my friends in a couple days of a sudden in

8 0

3 years ago

The cost of highlighters is proportional to the number of highlighters purchased. If a 4

andrew-mc [135]

Answer:

The cost per highlighter is $0.60

Step-by-step explanation:

I know this because to find the cost of each highlighter you would divide $2.40 by 4 so the answer would be $0.60.

Please give brainliest I'm trying to level up

3 0

3 years ago

Read 2 more answers

1.On which number line are –4 and its opposite shown?2.Which of the following describes the location of the opposite of the numb

anzhelika [568]

Answer:

1. d

2. 2

Step-by-step explanation:

if it's a negative it's opposite will be a positive and vice versa

8 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

Estimate the sum. Round each number to the nearest whole number, then add. 9 1/2 + 7 1/8

borishaifa [10]

Answer:

12 1/8

Step-by-step explanation:

4 0

3 years ago