Could someone please help

Mathematics

1 answer:

just olya [345]3 years ago

7 0

First, find the area: Area (A) = length (L) x width (w) = 14 x 7 = 98 ft²

Next, find the cost:
98 ft² x $.75/ft² = $73.50

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In the last election, 60% of the class members voted. If the class has 120 members, how many members voted in the last election?

horrorfan [7]

That is a pretty apathetic class. now if you want to to this one, it is mental math. 60% is = to 50% +10%
50% of 120 is 60 and 10% of 12
60+12 is 72
the answer is 72 or A
hope this helps

6 0

4 years ago

Read 2 more answers

A USA Today/CNN/Gallup survey of 369 working parents found 200 who said they spend too little time with their children because o

KengaRu [80]

Answer: a. 0.542

b. 0.051

c. $(0.491,\ 0.593)$

Step-by-step explanation:

Let p be the population proportion of parents spend too little time with their children because of work commitments

As per given , we have

n= 369

$\hat{p}=\dfrac{200}{369}=0.542005420054\approx0.542$

Since the sample proportion is the best estimate for the population proportion.

So , the point estimate of the proportion of the population of working parents who feel they spend too little time with their children because of work commitments = 0.542

z-value for 95% confidence interval : $z_{\alpha/2}=1.96$

Margin of error : $E=z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$E=(1.96)\sqrt{\dfrac{0.542(1-0.542)}{369}}\\\\=0.0508364564574\approx0.051$

The margin of error = 0.051

Confidence interval : $\hat{p}\pm E$

$0.542\pm0.051\\\\=(0.542-0.051,\ 0.542+0.051)\\\\=(0.491,\ 0.593)$

95% confidence interval estimate of the population proportion of working parents who feel they spend too little time with their children because of work commitments : $(0.491,\ 0.593)$

6 0

4 years ago

Simplify the expression using the rules for exponents

blagie [28]

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{(a^{-3}b^{-1}c^{-5})^{-2}}{(a^5b^4c^2)^5}\implies \stackrel{\textit{distributing the exponent}}{\cfrac{(a^6b^2c^{10})}{(a^{25}b^{20}c^{10})}}\implies \cfrac{c^{10}c^{-10}}{a^{25}a^{-6}b^{20}b^{-2}} \\\\\\ \cfrac{c^{10-10}}{a^{25-6}b^{20-2}}\implies \cfrac{c^0}{a^{19}b^{18}}\implies \cfrac{1}{a^{19}b^{18}}$