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ivanzaharov [21]
3 years ago
11

Jordan buys a car for £5000. It depreciates buy 23% per year. How much is it worth after 5 years?

Mathematics
1 answer:
Basile [38]3 years ago
3 0
The answer can be computed as follows:
                                   worth = £5000(1 - 0.23)^(5) = <span>£1353.39
It is approximately worth </span><span>£1353.39 after 5 years.</span>
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Q1. Find y, if √12 - √147 + y√3 = 0
o-na [289]

Answer:

Q1. y = 5 Q2.  (√2 - √3)/2

Step-by-step explanation:

Q1

√12 - √147 + y√3 = 0

Taking -√147 and √12 to the right hand side, we have

y√3 = √147 - √12

y√3 = √(3 × 49) - √(3 × 4)

y√3 = √3 × √49 - √3 × √4

y√3 = √3 × 7 - √3 × 2

y√3 = 7√3 - 2√3

y√3 = 5√3

Dividing both sides by √3, we have

y√3/√3 = 5√3/√3

y = 5

Q2

Sin45° - Cos30°

Since Sin45° = √2/2 and Cos 30° = √3/2

Substituting these values into the equation, we have

Sin45° - Cos30° = √2/2 - √3/2

Taking L.C.M of both factors, we have

Sin45° - Cos30° = (√2 - √3)/2

6 0
3 years ago
Study the geometric sequence {-4, -84, -1764, -37044, ...}.
Nonamiya [84]

Answer:

              \bold{a_n=(-4)21^{n-1}}

Step-by-step explanation:

a_1=-4\,,\ a_2=-84\,,\ a_3=-1764\,,\ a_4=-37044\quad\implies\ \ r=21

{-84:(-4)=21 and -1764:(-84)=21 and -37044:(-1764)=21}

geometric sequence formula:   a_n=a_1r^{n-1}

a_1=-4\quad and \ \ r=21

a_n=(-4)21^{n-1}

3 0
3 years ago
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Have 3896minutes in creadit on her card
5 0
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total of 393 tickets were sold for the school play. They were elther adult tickets or student tickets. The number of student tic
Andrews [41]
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Explanation:

Let x be the number of student ticket
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x = 2y

Substitute x value:

2y + y = 393
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y = 131

Substitute y value in one of the equation above:

x = 2(131)
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8 0
3 years ago
Which number is irrational? A.-4 B.2/9 C.sqrt of 11 D.8.26... (repeating 6 only)
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That would be  sqrt 11. 
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3 years ago
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