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IgorLugansk [536]
3 years ago
10

Rewrite the equation in vertex form. Name the vertex and y-intercept. y=3/5x^2+30x+382

Mathematics
2 answers:
professor190 [17]3 years ago
8 0

Answer:

answers for completing squares

Step-by-step explanation:

1)d:-5/3,5/3

2)d:12.7

3)c:-1,-11

4)d:3/2+-sqrt69/6

5)a:y=3/5(x+5)2+21/5 vertex: (-5,21/5) y intercept (0,382)

Serga [27]3 years ago
7 0
<span>(y-7) = 3/5 (x+25)^2 so the y intercept is -7 and the vertex is 35

</span>
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Answer:

y=4x-8.5

Step-by-step explanation:

Use point- slope form, since you are given one point and one slope.

y-y₁=m(x-x₁)

Plug coordinates and slope in.

y-(-1/2)=4(x-2)

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Step-by-step explanation:

1.) First, you need to take the whole numbers (9 and 1) and set them aside.

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3.) Multiply the denominators by each other as well. The denominators are the numbers on the bottom. This will be the denominator of your answer.

4.) Now, you need to multiply your whole numbers (9 and 1) together.

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Your answer will be 9 1/66.

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4 0
3 years ago
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
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Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

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Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

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P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

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