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IgorLugansk [536]

2 years ago

10

Rewrite the equation in vertex form. Name the vertex and y-intercept. y=3/5x^2+30x+382

2 answers:

professor190 [17]2 years ago

8 0

Answer:

answers for completing squares

Step-by-step explanation:

1)d:-5/3,5/3

2)d:12.7

3)c:-1,-11

4)d:3/2+-sqrt69/6

5)a:y=3/5(x+5)2+21/5 vertex: (-5,21/5) y intercept (0,382)

Serga [27]2 years ago

7 0

<span>(y-7) = 3/5 (x+25)^2 so the y intercept is -7 and the vertex is 35

</span>

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3 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

So

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

So

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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2 years ago

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Answer:

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Step-by-step explanation:

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