For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)
Answer:
5/6. Is this what u are looking for?
Step-by-step explanation:
Step 1 Simplify:2x(6)-19=-9 to 12x+-19=-9
Step 2 Add 19 to both sides: 12x-19+19=-9+19. You should get 12x=20
Step 3 Divide 12 on both sides: 12x/12=10/12
x=10/12. Simplified= x=5/6
