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svet-max [94.6K]
3 years ago
15

△ABC≅△DEF What side corresponds to side line segment AB

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
The corresponding segment is A: Line segment DE
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Tcecarenko [31]

Answer:

4

Step-by-step explanation:

Hope this helps!

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Am I right or wrong?​
netineya [11]

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First off, I love your handwriting, 2nd i think ur correct!

Step-by-step explanation:

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LetT: P2 → P4be the linear transformationT(p) = 4x2p.Find the matrix A for T relative to the basesB = {1, x, x2}andB' = {1, x, x
ExtremeBDS [4]

Answer:  The required matrix A is

A=\left[\begin{array}{ccc}0&0&0\\0&0&0\\4&0&0\\0&4&0\\0&0&4\end{array}\right]_{5\times3} .

Step-by-step explanation:  We are given the following linear transformation :

T:P^2\Rightarrow P^4,~~~~~~~~~~~~~T(p)=4x^2p.

We are to find the matrix A relative to the bases B=\{1,x,x^2\} and B^\prime=\{1,x,x^2,x^3,x^4\}.

We have

T(1)=4x^2\times1=4x^2=0\times1+0\times x+4\times x^2+0\times x^3+0\times x^4,\\\\T(x)=4x^2\times x=4x^3=0\times1+0\times x+0\times x^2+4\times x^3+0\times x^4,\\\\T(x)=4x^2\times x^2=4x^4=0\times1+0\times x+0\times x^2+0\times x^3+4\times x^4.

Therefore, the matrix A is of order 5 × 3, given by

A=\left[\begin{array}{ccc}0&0&0\\0&0&0\\4&0&0\\0&4&0\\0&0&4\end{array}\right]_{5\times3} .

Thus, the required matrix A is

A=\left[\begin{array}{ccc}0&0&0\\0&0&0\\4&0&0\\0&4&0\\0&0&4\end{array}\right]_{5\times3} .

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3 years ago
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kozerog [31]

\tt \: 2x + 4 > 16

Move the constant to the right-hand side and change its sign

\tt \: 2x > 16 - 4

Subtract the numbers

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Divide both sides of equation by 2

\boxed{ \sf \: x > 6}

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