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3 years ago

I want help ,i want an answer

Mathematics

1 answer:

devlian [24]3 years ago

8 0

Answer:

Can’t really help you with the number line from here, but I can tell you that for you second question, the order of them is:

-3/5, -1/2, 1/3, 4/5, 8/9

Step-by-step explanation:

-3/5 is the largest negative number, meaning it’s the fastest away from zero, so really the smallest.

-1/2 is the only other negative.

1/3 Is the smallest positive number becasue there it is less than 1/2

4/5 is larger than 1/2, but not larger than 8/9

8/9 is the largest.

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Eric works for an airline, and he needs to calculate the weight of passengers and luggage before takeoff. The number of

igomit [66]

Answer:

Step-by-step explanation:

To complete the question, here are the answer choices:

A) =A1*A2*A3*A4

B) =A1*A2+A3+A1*A4

C) =A1*(A2+A3+A1)*A4

D) =A1*A2+(A3+A1)*A4

We first need to multiply A1 and A2, this will give weight of passengers.

To get weight of luggage, we multiply A1 and A4.

We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.

So we will get

A1*A2 + A1*A4 + A3

This is given in a different order in Option B. Hence, option B is right.

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3 years ago

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What is the measure of angle one

ololo11 [35]

Angle one would be 61

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3 years ago

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Can Someone Help Me Please

iren2701 [21]

Answer:

Step-by-step explanation:

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3 years ago

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Solve the system of equations using substitution

Ira Lisetskai [31]

Answer:

x=-1, y=9. (-1, 9).

Step-by-step explanation:

6x-y=-15

x+2y=17

--------------

y=6x-(-15)

y=6x+15

x+2(6x+15)=17

x+12x+30=17

13x=17-30

13x=-13

x=-13/13

x=-1

-1+2y=17

2y=17-(-1)

2y=17+1

2y=18

y=18/2

y=9

3 0

4 years ago

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

Let's verify each case to determine the solution

case A) $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

case B) $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

case C) $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

case A) $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

the answer is

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

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3 years ago

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