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Kobotan [32]
4 years ago
12

Which particle diagram represents a sample of matter that can not be broken down by chemical means?

Chemistry
2 answers:
solniwko [45]4 years ago
3 0
In the picture below that I attached, the answer is D. 

In the diagram, there are only one type of element depicted. 

Liula [17]4 years ago
3 0

Answer;

Considering the attached image;

The correct answer is D.

Explanation;

-An element is a substance that can not be broken down into simpler substances by ordinary chemical means. Example, iron, gold, hydrogen , carbon, oxygen , etc.

-Elements are made of atoms. An atom is the smallest particle of an element that can take part in a chemical reaction. Atoms of different elements are different. Atoms of one element are basically alike.

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Measuring how quickly a reactant disappears is one way to measure the ______________of the reaction
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Explanation:

More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.

Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.

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4 years ago
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Saturated hydrocarbons are major components of
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Write a balanced chemical equation to show the reaction of naoh with the diprotic acid h2so4.
Thepotemich [5.8K]

Answer:

2NaOH +H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O

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2NaOH +H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O

8 0
4 years ago
.Name a letter never used in any element symbol?​
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8 0
3 years ago
Mercury and oxygen react to form mercury(II) oxide, like this: 2Hg (l) + O2 (g) → 2HgO (s) At a certain temperature, a chemist f
enyata [817]

Answer:

<u></u>

  • <u>Kc = 12.4 M⁻¹</u>

Explanation:

<u>1) Chemical equilibrium</u>

  • 2Hg (l) + O₂ (g) ⇄ 2HgO (s) (the double arrow indicates an equilibrium reaction)

<u />

<u>2) Equilibrium constant, Kc:</u>

  • The equilibrium constant, Kc, is equal to product of the concentrations of each product,each raised to its stoichiometric coefficient / product of the concentrations of each reactant each raised to its stoichiometric coefficient.
  • Since the concentrations of liquid and solid substances remain practically constant, their value is incorporated into the constant Kc, and the equation only uses the concentrations of the aqueous or gaseous substances.

Thus, the equation to use is:

  • Kc = 1 / [O₂(g) ]

<u>3) Determine the concentration of O₂ (g)</u>

  • M = number of moles / volume in liters

  • Number of moles = mass in grams / molar mass

  • Number of moles of O₂ (g) = 13.4 g / 32.00 g/mol = 0.419 mol

  • M = 0.419 mol / 5.2 liter = 0.0806 mol / liter = 0.0806 M

<u>4) Compute Kc</u>

  • Kc = 1 / 0.0 806 M = 12.4 M⁻¹ ← answer
4 0
3 years ago
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