Answer:
| 10 -10 1 |
| 1 -2 -4 |
| -8 13 -24|
Step-by-step explanation:
First multiply each element in matrix A, this gives:
| -6 - 2 -3 |
| 1 -6 -4 |
| -4 5 0 |
Now we multiply each element in matrix B by 4, this gives:
| -16 8 -4 |
| 0 -4 0 |
| 4 -8 24 |
Finally subtract this from the first matrix ( subtracting element by element) gives:
| 10 -10 1 |
| 1 -2 -4|
| -8 13- 24|
9514 1404 393
Answer:
3
Step-by-step explanation:
Let x represent the number. The problem statement tells you ...
2/3(3x +6) = 10
2x +4 = 10 . . . . . . use the distributive property
x +2 = 5 . . . . . . . . divide by 2
x = 3 . . . . . . . . . . .subtract 3
The number is 3.
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<em>Comment on the solution</em>
The above shows an "alternative" solution method. The more usual way this might be done is ...
2(3x +6) = 30 . . . . . multiply by 3 to clear fractions
6x +12 = 30 . . . . . . . eliminate parentheses
6x = 18 . . . . . . . . . . . subtract 12
x = 3 . . . . . . . . . . . . divide by 6
Answer: -10x + 1y = 2
Step-by-step explanation:
The standard formula says that Ax + By = C where A is the coefficient of the x variable, B is the coefficient of the y variable, and C is the constant value.
y = 10x + 2 Subtract 10x from both sides of the equation .
-10x -10x
-10x + 1y = 2
Answer : The average rate of change between 1 year and 4 years of age is 7.33 lbs per year.
Step-by-step explanation :
As we know that the average rate of change between two input values is the total change of the output values divided by the change in the input values.
From the table, we conclude that:
The weight of 1 year of age = 20 lbs
The weight of 4 years of age = 42 lbs
Now we have to determine the average rate of change between 1 year and 4 years of age.
The input (years) has changed by = 4 years - 1 year = 3 years
The output has changed by = 42 lbs - 20 lbs = 22 lbs
Average rate of change = Output ÷ Input
Average rate of change = 
Average rate of change = 7.33 lbs per year
Therefore, the average rate of change between 1 year and 4 years of age is 7.33 lbs per year.
