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amm1812
3 years ago
14

If JK LM, which statement is true?

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

No! It's the fact they meet at a 90 degree angle.... Please don't answer the questions unless you know the answer... Thanks you

Step-by-step explanation:

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Consider the system of equations:
AVprozaik [17]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Since, we know that in Elimination method we have to first the value of "x" or either "y". For that we have to multiply a number which makes the both equation's "x" or "y" equal so that we cut cancel it and find the solution.

Here's an example:

Like, in here

Equation 1: - 2x + 3y = 9

Equation 2: - 8x - 7y = 10

We can see that in "Equation 1" the first number is "- 2x" and in "Equation 2" the first number is "-8x". So, what we do in Elimination method is that we have to make the first number of both the equations equal or same.

Eg:

- 2x + 3y = 9.

- 8x + 7y = 10--(ii)

Now,we can see that in "Equation 2" the first number is "8x" whereas in "Equation 1" the first number is "-2x". We have to multiply with any number that makes the both the first number of equation is same.

So, I'm taking the number "4" to multiply it with equation 1, which gives us the result,

4( - 2x  + 3y) = 9 \times 4 \\  \\  \leadsto - 8x + 12y = 36

Now, we've subtract both the equation to get the results.

\boxed{ \frak \red{brainlysamurai}}

6 0
2 years ago
The point (-2,3) is the solution to which of the following systems of equations?
SpyIntel [72]

In what form?!?!?!?!?!?!?

3 0
3 years ago
Read 2 more answers
Next four multiple of the fraction 3/5
OleMash [197]
6/10, 9/15, 12/20, 15/25
7 0
3 years ago
Read 2 more answers
HELP
dsp73

Answer:

1)  4

2) 3

3) 9

4) 6

5) 3/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7By%20-%203%7D%20%20-%20%20%5Csqrt%7By%7D%20%20%3D%20%20-%203" id="TexFormula1" tit
Soloha48 [4]

Answer:

no solutions exist

Step-by-step explanation:

\sqrt{y-3} = \sqrt{y} -3 \\ y-3 = y + 9 -6\sqrt{y} \\ 6\sqrt{y} = 12 \\ \sqrt{y} = 2 \\ y = 4

verify

\sqrt{4-3} - 2 = -3 \\ 1-2 = -3 \\ -1= -3

not true, the equation is impossible

4 0
3 years ago
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