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Which of the following describes the sum in terms of p and q?(1 point)

snow_tiger [21]

The description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

<h3>How to describe the sum in terms of p and q?</h3>

The summation expression is given as:

p + (-q)

In the above summation expression, we assume that:

p ⇒ Positive number

- q ⇒ Negative number

Having said that:

The expression -q would go in the negative direction if plotted on a number line

This means that the description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

Hence, the description of the summation expression given as p + (-q) is the sum, p + (-q), is the number located a distance, |p|, from , q, in the negative direction.

Read more about expressions at:

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6 0

2 years ago

20% 0f =100 want to know the answer to this question

Arturiano [62]

Answer:

That would be 20.

Step-by-step explanation:

Hope this helps

3 0

3 years ago

Read 2 more answers

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0

3 years ago

Solve the system of equations.

Xelga [282]

Answer:

b. x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

3x +2y +z = 10
9x -6y +z = 0
x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

(3x +2y +z) -3(x -y -3z) = (10) -3(-10)

5y +10z = 40 . . . . simplify

y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

z = 15 -6y . . . . . subtract 6y from [eq4]

y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

-11y +30 = 8 . . . . . simplify

-11y = -22 . . . . . . . subtract 30

y = 2 . . . . . . . . . . . divide by the coefficient of y

z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

x - 2 -3(3) = -10

x -11 = -10 . . . . . . . . simplify

x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0

4 years ago

For which value of a does Limit of g(x) as x approaches alpha not exist?

Hunter-Best [27]

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

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7 0

2 years ago