Answer:
2+2=4, because 2 is made up of two ones and theres 2 2's which makes it 1+1+1+1=4
Step-by-step explanation:
Answer:
$184383.7
Step-by-step explanation:
Using the formula :
V = Pe^rt
Principal, P = 85,800
Rate of interest, r = 8.5% = 0.085
Time = 9
V = 85800 * e^(0.085*9)
V = 85800 * e^0.765
V = 85800 * 2.1489943
V = 184383.71
V = $184,383.7
Answer:
Emanuel did a mistake in her first step.
Step-by-step explanation:
The given expression is
Emanuel solve this problem but she did a mistake in her first step. She distributes negative sign with 1 and 2 both which is incorrect. We can write negative sign with either 1 or 2 but not both.
Correct steps are:
Step 1:
Step 2:
Step 3:
Therefore, she did a mistake in her first step.
Answer:
a) The probability that a box containing 3 defectives will be shipped is ![51.74\%](https://tex.z-dn.net/?f=51.74%5C%25)
b) The probability that a box containing only 1 defective will be sent back for screening is ![17.39\%](https://tex.z-dn.net/?f=17.39%5C%25)
Step-by-step explanation:
Hi
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 20 items of the box (discounting the 3 defectives) as the possible ways to succeed, so
Finally we need to compute
, therefore the probability that a box containing 3 defectives will be shipped is
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 22 items of the box (discounting the defective 1) as the possible ways to succeed, so
Then we need to compute
, therefore the probability that a box containing 1 defective will be shipped is
Finally the probability that a box containing only 1 defective will be sent back for screening will be ![P(BS)=1-P(S)=1-0.8260=0.1739=17.39\%](https://tex.z-dn.net/?f=P%28BS%29%3D1-P%28S%29%3D1-0.8260%3D0.1739%3D17.39%5C%25)