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4 years ago

What is the explicit formula for the sequence? 7, 14, 21, 28, 35, . . .

Mathematics

2 answers:

qaws [65]4 years ago

7 0

Count By 7's Each Time

larisa86 [58]4 years ago

6 0

You’re supposed to +7 each time

You might be interested in

Use the ratio table to solve the percent problem.

aliina [53]

It would be; 90 * 20%
= 90 * 0.20
= 18

In short, Your Answer would be 18

Hope this helps!

4 0

3 years ago

I need step by step explanation for this!!

Naily [24]

Hello! :)

Answer:

$\huge\boxed{751}$

Let the smallest digit, or the units' digit, be equal to x:

Tens' digit is four more, therefore:

x + 4 represents the tens' digit.

Hundreds' digit is 2 more than the tens' digit, so:

2 + (x + 4), or x + 6 represents the hundred's digit.

These all sum up to 13, so write an expression to represent this:

x + (x + 4) + (x + 6) = 13

Combine like terms:

3x + 10 = 13

Subtract 10 from both sides:

3x = 3

Divide both sides by 3:

x = 1

Find the digits using the rules listed above:

Hundreds' digit: (1) + 6 = 7

Tenths' digit: (1) + 4 = 5

Units' digit: 1 = 1

Therefore, the number is:

751.

4 0

3 years ago

Read 2 more answers

It is estimated that t-weeks into a semester, the average amount of sleep a college math student gets per day S(t) decreases at

goldenfox [79]

Answer:

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

Step-by-step explanation:

Before to getting started ,we have to consider the function which represents sleep decline rate S'(t) = $-3te^{t^{2} } \\$

Since this function is interpreted in this case as a rate of change, we can deduce this funcion is the first derivative of the function of average amount of sleep (S(t)).

In order to find S(t), we will integrate S'(t)

$\int\limits^ {} -3t3e^{t^{2} } \, dx \\$

This case corresponds to intergration by substitution

Substituting u= $x^{2} \\$

Computting the differential of u

$\frac{du}{dt} =2tdt\\$

Now, let's go back to our integral and write it in terms of u, using both definition of u and its defferential.

$\int\limits^{}-3te^{u} \, \frac{1}{2t}du \\\\\int\limits^{}\frac{-3}{2} e^{u}du\\$

The integral of a exponential function is itself. So the result is:

$\frac{-3}{2} e^{u} +c$

Now substitute u back in:

$\frac{-3}{2} e^{t^{2} } +c$

This answer correspond to function of average amount of sleep.

We know that when the semester begins (t=0) , math students sleep an average of 8.1 hours per day so we will use this info in order to find the value of c.

$s(0)=\frac{-3}{2} e^{0^{2} } +c=8.1\\\\\frac{-3}{2} +c=8.1$