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Alex_Xolod [135]
3 years ago
14

The greatest common factor of 56f 3g 2 and 70fg 3 is 7fg 3.

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Hello!

Your answer is False!

Alex777 [14]3 years ago
4 0
You can see 7*3*2*f*g is not the same as 7fg3, so the statement is false.
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Identify the function as a growth or decay function. y = (1/2)x
tangare [24]

Answer:

This would be a decay function.

Step-by-step explanation:

When a function is a growth function that means that it is growing but a decay function means that it is getting smaller.

8 0
3 years ago
Use gcf distributive property to find the sum of 28 and 80.
Anna71 [15]

Step-by-step explanation:

The GCF of 28 and 80 is 4.

<u>Distribute 4 for 28 and 80, then solve:</u>

4(7) + 4(20) = 28 + 80

4(7 + 20) = 28 + 80

4(27) = 28 + 80

108 = 80 + 28

7 0
2 years ago
What is the slope of a line that is parallel to the line y = 3/4 + 2?
Elodia [21]
3/4 because it’s parallel so it has the same slope. It just doesn’t pass through the same line.
7 0
3 years ago
Hannah has a bag containing 2 Red, 4 purple, 4 Blue and 2 Green
juin [17]

Answer:

1/18

Step-by-step explanation:

there are 12 marbles in the bag

P(choose red) = 2/12 = 1/6

P(choose blue after replacement) = 4/12 = 1/3

P(choose red, then blue with replacement) = (1/6)(1/3) = 1/18

7 0
2 years ago
Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .
Masja [62]

Answer:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

Step-by-step explanation:

Lets   y  =  f(x)   in a cartesian coordinates

Having three zeros:

x = -3       ⇒   x  = -2      ⇒   and   x = 1  

That meas that if   x  takes the above mentioned  values " y " must be zero

therefore  y  must be of the form

f (x)  =  y  =  ( x + 3 ) *  ( x +  2 ) * ( x - 1 )     (1)

In that case for y to be zero one of the factors should be zero or

y  =  0        x  + 3 = 0    and  x = - 3  is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x =  3 ,  y have to be 11, therefore we plug in equation (1)  that value to see what happens

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )

11  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1)   =  6*5*2  = 60

Then we adjust the expression (1) to meet the condition of the function passing through point  ( 3 , 11) as:

y  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60    (2)

and check to see if we did right

for y to be zero      x   can be    x = - 3    x  =  -2   and  x = 1 in all these cases y = 0.  And if  x  =  3   in equation (2)  y = 11. And that what we want to shown. Then the solution is:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

8 0
3 years ago
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