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erik [133]
4 years ago
5

I need help on this one as well

Mathematics
1 answer:
Pepsi [2]4 years ago
8 0
11. the midpoint = 6 cm.
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What is uv + v u = –1 and v = –1.
Lina20 [59]
Answer = 0
-1(-1)=1
1 + -1 = 0
3 0
3 years ago
Read 2 more answers
The following frequency table summarizes the number of children that dads in Dads Club have.
attashe74 [19]

Answer:

C

Step-by-step explanation:

Now there are 6+4+8+1+1=20 dads in the Dads Club.

Fewer than 3 children have

  • 1 child - 6 dads
  • 2 children - 4 dads.

So, 6+4=10 dads have fewer than 3 children.

The probability that the dad of Dads Club has fewer than 3 children is

Pr=\dfrac{10}{20}=0.5 \text{ or } 50\%.

The probability that the next dad to join Dads Club has fewer than 3 children is reasonable to be 50%.

8 0
3 years ago
Read 2 more answers
From a thin piece of cardboard 50 in. by 50 in., square corners are cut out so that the sides can be folded up to make a box. Wh
mixer [17]

Answer:

When dimension of box is 33.33 inches × 33.33 inches ×8.33  then its volume is maximum and is 9259.26 cubic inches.

Step-by-step explanation:

Let h be the length (in inches) of the square corners that has been cut out from the cardboard and that would be the height of the cardboard box.

Since the squares have been cut from cardboard, both sides of the cardboard would reduce by 2h.

Thus, The dimension of box is  (50 – 2h) × (50 – 2h) × h in dimensions.

The volume V of rectangular box = (Length × Breadth × Height) cubic inches.

V=(50-2h) \times (50-2h) \times h

V=(50-2h)^2 \times h  ..............(1)

Using (a-b)^2=a^2+b^2-2ab

V=h(2500+4h^2-200h)

V=2500h+4h^3-200h^2

For obtaining a box of maximum volume, maximize V as a function of h.


Differentiate both sides with respect to h,

\frac{dV}{dh}=2500+12h^2-400h

\frac{dV}{dh}=4(625+3h^2-100h)

Solving quadratic equation,625+3h^2-100h

\frac{dV}{dh}=4(3h^2-25h-75h+625)

\frac{dV}{dh}=4(h(3h-25)-25(3h-25))

\frac{dV}{dh}=4((h-25)(3h-25))

For maximum, \frac{dV}{dh}=0  

thus,4((h-25)(3h-25))=0

⇒ h= 25 or h=\frac{25}{3}

Now check (1) for h= 25 and h=\frac{25}{3}.

h= 25 is not possible as when h is 25 inches then length and breadth becomes 0.

When h=\frac{25}{3}.

(1) ⇒ V=(50-2(\frac{25}{3}))^2 \times\frac{25}{3}=9259.2592593  

This is the maximum volume the box can assume.

Thus, when dimension of box is 33.3 inches × 33.3 inches ×8.3  then its volume is maximum and is 9259.26 cubic inches.

6 0
3 years ago
Choose an expression for the number of scoops Zack needs to fill both feeders. Will make brainliest if u tell me in under a minu
yan [13]

Answer:

C

Step-by-step explanation:

Please mark brainliest

3 0
3 years ago
1) In Math class Mike and Karen are looking at two numbers: 152 and 33 +. 53.
vladimir2022 [97]

Answer:

Mike is right. 152 is larger than 33 + 53/

Step-by-step explanation:

First we need to add 53 + 33 to see if it will equal up ro 152. So 53 + 33 = 86.

86 is less than 152, so Mike is correct and Karen is wrong, as usual.

7 0
3 years ago
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