Answer:
7/15
Step-by-step explanation:
Well 4/5 - 1/3 = 12 / 15 - 5 / 15 which is equal to 7/15, but there aren't any expressions in your question.
Answer:
Step-by-step explanation:
We are looking for the value of x so that the function has the given value in the following:
1) h(x) = -7x; h(x)=63
From the function given above,
If h(x) = 63, then,
h(x) = 63 = -7x
-7x = 63
Dividing the left hand side and right hand side of the equation by -7, it becomes
-7x/-7 = 63/-7
x = - 9
2) m(x) = 4x + 15; m(x)=7
From the function given above,
If m(x) = 7, then,
m(x) = 7 = 4x + 15
7 = 4x + 15
4x = 15 - 7 = 8
Dividing the left hand side and right hand side of the equation by 4, it becomes
4x/4 = 8/4
x = 2
3) q(x) = 1/2x - 3; q(x) = -4
From the function given above,
If q(x) = - 4, then,
q(x) = - 4 = 1/(2x - 3) =
Cross multiplying,
-4(2x-3) = 1
-8x +12 = 1
Collecting like terms,
-8x = 1 - 12
-8x = -11
Dividing the left hand side and right hand side of the equation by -8, it becomes
-8x/8 = -11/-8
x = 11/8
Answer:
4/40
Step-by-step explanation:
you can reduce this to 1/10
multiplying 4 by both 1 and 10 will give you the fraction 4/40 both can be divided by 4 and that's how it can reduce to the 1st fraction (1/10)
Check the picture below.
now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.
since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.
its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%204p%28x-%20h%29%3D%28y-%20k%29%5E2%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cend%7Barray%7D%20%5Cqquad%20%5Cbegin%7Barray%7D%7Bllll%7D%20vertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D-5%5C%5C%20k%3D7%5C%5C%20p%3D-2%20%5Cend%7Bcases%7D%5Cimplies%204%28-2%29%5Bx-%28-5%29%5D%3D%5By-7%5D%5E2%20%5C%5C%5C%5C%5C%5C%20-8%28x%2B5%29%3D%28y-7%29%5E2%5Cimplies%20x%2B5%3D%5Ccfrac%7B%28y-7%29%5E2%7D%7B-8%7D%5Cimplies%20%5Cboxed%7Bx%3D-%5Ccfrac%7B1%7D%7B8%7D%28y-7%29%5E2-5%7D)
