8x-4y=28
8x-4y-8x=28-8x
-4y=28-8x
(-4y)/-4=(28-8x)/-4
y=-7+2x
y=2x-7
Answer:
1/36
Step-by-step explanation:
There's only 1 way to get the sum of 2.
1,1
The quadratic formula is:
x=(-b±√(b^2-4ac))/(2a) for the quadratic of the form ax^2+bx+c
The discriminant is the (b^2-4ac) part of the quadratic formula.
Let d=(b^2-4ac). If:
d<0: There are no real roots.
d=0: There is one real root.
d>0: There are two real roots.
In this case the discriminant is:
(-6)^2-4*3*4
36-48
-12
Since -12<0 there are no real roots for the equation 3x^2-6x+4.
1. cos (angle) = adjacent leg / hypotenuse
cos(50) = 10/X
x = 10/cos(50)
x = 15.6 feet
2.
tan(angle) = Opposite leg / adjacent leg
tan(5.5) = 600/x
x = 600/tan(5.5)
x = 6,231.2 feet.