What is this can you guys help

Which is the graph of f(x) = (x + 3)(x - 2

yanalaym [24]

Answer:

Step-by-step explanation:

f(x) = (x + 3)(x - 2) has two zeros: One stems from (x + 3) = 0 and is (-3, 0); the other stems from (x - 2) = 0 and is (2, 0).

The axis of symmetry is a vertical line located halfway between -3 and 2:

x = -1/2.

The graph opens up because the given (x + 3)(x - 2) has a positive leading coefficient (+1).

With this information we can eliminate the last two possible answers. Note that the x-intercepts of the first graph are -3 and 2, Thus, the first graph is the correct one.

5 0

3 years ago

I'm so lost with this math problem

TEA [102]

Answer:

A: 1/5

B: 3/5

Step-by-step explanation:

3 0

3 years ago

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HELP ME PLEASE!!! I WILL MARK YOU AS A BRAINLIEST!!

astra-53 [7]

Answer:

2.5 eggs per chicken

Step-by-step explanation:

8 0

3 years ago

1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of

Sonbull [250]

Answer:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=120$ represent the sample mean

$s=20$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =100$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=10-1=9$

Conclusion

Since is a tao tailed test the p value would be:

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

8 0

3 years ago

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There are 10 milligrams of sugar in a store bought juice. How many centigrams of sugar does the juice contain? A) 1 B)10 C)100 D

EastWind [94]

B is the answer. Hope this helps!

4 0

3 years ago

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