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melisa1 [442]
3 years ago
11

How is percentages and conversions used in the healthcare field

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
Sometime you have to convert medicine amounts or maybe how much you have to cut something in surgery that you have to convert you also might use percentages figuring out the percent of something to go in a specific medication
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Mai's mother was 28 when Mai was born. Mai is now 12 years old. In how many years will Mai's mother be twice Mai's Age
noname [10]

Answer:

4

Step-by-step explanation:

Let x = the number of years

In x years, Mai's mother's age will be: 28 + x

                         and Mai's age will be:  12 + x

Then,                                      28 + x = 2(12 +   x)

Distribute the 2                      28 + x =    24 + 2x

Subtract 24 from each side     4 + x =            2x

Subtract x from each side             x = 4

In four years, Mai's mother will be twice Mai's age.

<em>Check: </em>

28 + 4 = 2(12 + 4)

   32   = 2 ×  16

   32   =   32

6 0
3 years ago
the sum of the recipocal of two consecutive even number is 7/24.one number is 6.the other number will be​
coldgirl [10]

Answer:

8

Step-by-step explanation:

The numbers are 6 and 2x, then:

  • 1/6 + 1/(2x) = 7/24
  • 1/3 + 1/x = 7/12
  • (x+3)/(3x) = 7/12
  • 12(x+3) = 7*3x
  • 12x + 36 = 21x
  • 21x - 12x = 36
  • 9x = 36
  • x = 4

The other number is 2*4 = 8

6 0
3 years ago
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
Write an equivalent expression by distributing the "_" sign outside the parentheses: -k - (-6.2m+1)​
nevsk [136]

Answer:

-k + (6.2m - 1)

Step-by-step explanation:

You distribute the negative to everything in the parentheses and change the sign to addition.

3 0
3 years ago
PLEASE HELP Which of the following diagrams shows a line that is tangent to the circle?
Irina18 [472]

Answer:

From google answers.. the answer is D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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