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IgorC [24]
3 years ago
6

Chris Christina collects stamps she is 47 stamps and all she has 20 from Europe the number of African stamps is 2 times the numb

er of Asian stamps how many Stamps from each of these three colors does she have using reasoning to write this numerical expression show work​
Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Let x represent the number of stamps from Europe.

Let y represent the number of stamps from Africa.

Let z represent the number of stamps from Asia.

She has 47 stamps in all. This means that

x + y + z = 47 - - - - - - - - - - - 1

The number of African stamps is 2 times the number of Asian stamps. This means that

y = 2z

She has 20 stamps from Europe. Therefore, substituting x = 20 and y = 2z into equation 1, it becomes

20 + 2z + z = 47

3z = 47 - 20 = 27

z = 27/3 = 9

y = 2z = 2 × 9

y = 18

She has 20 stamps from Europe, 18 stamps from Africa and 9 stamps Asia.

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Is this question correct?
Andrews [41]

Answer:

10^20

3^11

3^24

10^12

Step-by-step explanation:

(10^2)^10=10^2*10=10^20

3^3*3^8=3^3+8=3^11

(3^3)^8=3^3*8=3^24

10^2*10^10=10^2+10=10^12

6 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
What ordered pair is a solution of the equation?<br><br> y=-2x-5
ioda

\sf \underline{Answer:}

Pick any value for x, like x = 0, plug it into the equation, and get the value for y. For x = 0,

2(0) + y = 5

y = 5

The ordered pair is (0,5). Find other ordered pairs using the same reasoning.

3 0
2 years ago
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The sum of two numbers is 53 . The larger number is 9 more than the smaller number. What are the numbers?
Illusion [34]

x + y = 53

x -y = 9  Adding both equations

2x = 62

x = 31 y = 22


6 0
3 years ago
Write the numeral for: Three thousand and five dollars and six cents.​
maxonik [38]

$3,005.06 is the answer for the question

6 0
3 years ago
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