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Virty [35]
3 years ago
12

(x+5)to the second power -4=12​

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

x = 3i

Step-by-step explanation:

(x+5)² - 4 = 12

simplify (x+5)²

x × x + 5 × 5 - 4 = 12

x² + 25 - 4 = 12

x² + 21 = 12

combine the like terms

x² = 12 - 21

x² = -9

square root both sides to solve for x

√x² = √-9

the square cancels the square root, so we have

x = √-9

x = 3i

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Decreases by 2 degrees

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T=110-2(Latitude)

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Which situation can be simulated by rolling a six-sided die once?
AleksandrR [38]

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A. Selecting one person from a group of four boys and two girls.

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8 0
3 years ago
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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

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KL = 19.85

\angle JKM =49

\angle JML =41

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Step-by-step explanation:

Given

MK = 30

NL = 13

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Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

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JL is a diagonal, and it is twice of NL.

JL = 2 * NL

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Solving (c): KL

To solve for KL, we consider triangle KNL where:

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KL^2 = NL^2 + NK^2

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Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

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