Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Answer:

Step-by-step explanation:
Given
See attachment
Required
Determine the slope of the line
From the attachment, we have the following points

and

The slope m is then calculated using:

Substitute values for the x's and y's




<em>Hence, the slope is 0</em>
Answer:
the answer is 14 2/3, hope this answers your question
Step-by-step explanation:
I’m pretty sure it’s D, if you count your boxes from the origin you go up four and over one so it would be 4x for slope
90 or 100 something like that.