A) -5(-1)+1
y=6
b) -5(0)+1
y=1
c)-5(1)+1
y=-4
d)-5(2)+1
y=-9
Domain (-4,2,1,-1)
Range(2,-4,-7)
Answer:
17
Step-by-step explanation:
Quadratic f(x) = (x -h)² +k has vertex (h, k) and axis of symmetry x=h. When k is negative, the number of real solutions is 2, because both branches of the function cross the x-axis.
In your equation, h = -3 and k = -8.
Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2
The answer would be D because when you divide 10 by 4 you take one fourth out of ten