Answer:
<h2> y = 13x - 80 </h2>
{Or, if you mean slope of 1/3: y = ¹/₃x - 4 }
Step-by-step explanation:
The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:
m = 13
(6, -2) ⇒ x₀ = 6, y₀ = -2
The point-slope form of the equation:
y + 2 = 13(x - 6)
So:
y + 2 = 13x - 78 {subtract 2 from both sides}
y = 13x - 80 ← the slope-intercept form of the equation
{Or, if you mean slope of ¹/₃: m = ¹/₃
The point-slope form of the equation: y + 2 = ¹/₃(x - 6)
y + 2 = ¹/₃x - 2 {subtract 2 from both sides}
y = ¹/₃x - 4 ← the slope-intercept form of the equation}
First, isolate 1/3s:
1/3s=12
Second, multiply both sides by 3 to get a singular value of s (just s):
s=36
Answer:
The Basic Identities are :
So for this question :
Solution
Question 1:
- Use of the area of squares to explain the Pythagoras theorem is given below
- The 3 squares given above have dimensions: a, b, and c.
- The areas of the squares are given by:
- The Pythagoras theorem states that:
"The sum of the areas of the smaller squares add up to the area of the biggest square"
Thus, we have:
Question 2:
- We can apply the theorem as follows:
![\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\ \\ c=\sqrt[]{676} \\ c=26 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2010%5E2%2B24%5E2%3Dc%5E2%20%5C%5C%20100%2B576%3Dc%5E2%20%5C%5C%20676%3Dc%5E2%20%5C%5C%20%5Ctext%7BTake%20square%20root%20of%20both%20sides%7D%20%5C%5C%20%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B676%7D%20%5C%5C%20c%3D26%20%5Cend%7Bgathered%7D)
Thus, the value of c is 26
3 is the slope, (0,-5) is the y-intercept of the graph.
